TRANSLATIONS

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So far I have at GD89 (pito) registered only these four glyphs:

Ab8-43 Ba9-5 Ca5-20 Yb3-103

Sun (or some other celestial body) is in the center, in A and C as a separate entity but in B and Y depicted inside.

I have already suggested that the top part in Ab8-43 (consequently also in the other three glyphs) are upside down versions of what we see at the bottom of the 'birth' (GD56, hanau) glyphs:

GD56 Aa4-55 Aa4-61

The bottom members in hanau glyphs sometimes show feet, sometimes the peculiar 'snaky' forms which seems to be the norm in the pito glyphs.

We note what presumably is a change of state from Aa4-55 to Aa4-61. One of the ears (cfr 'years') have disappeared and also the separate entity at mid bottom (the 2nd 'year'?) has been released.

The 'snaky' arm (maybe representing the raw nature character of the 1st 'year') has developed into a 'barren' Y-form - after 'cooking' the movements of the 'snake' has stopped.

The remaining (y)ear has a semi-circular form. It is on the right and forward side, i.e. represents present / future (because the left side reprents tu'a).

Here I hesitate. Is it reasonable to call the 1st 'year' side of Aa4-61 (and of Aa4-55) tu'a? In an absolute (stationary) view tu'a should be the back side of the year, i.e. the 2nd half of the year.

Glyphs appearing in the part of the text which describes the 2nd 'year' are 'inside' the tu'a phase. The left side of such glyphs may also be 'inside' the same phase, but suppose (as is the case with Aa4-61) that all glyphs at left in the text are 'outside' (describing the 1st 'year'). It then feels strange to call the left side of Aa4-61 tu'a.

The semi-circular form surely must represent the land (in contrast to the sea). At midsummer (the point of 'cooking') land does not disappear. The land presumably exists between spring and autumn equinox.

In Ab8-43 we can see an imbalance - the left bottom 'snake' is short, while the right one is correspondingly (?) long. This is certainly a sign. The bottom part of pito glyphs ought to have the same meaning as the bottom part of hanau glyphs.

There are many more glyphs of the hanau type to study than the very few pito glyphs and a comparison shows that an imbalance exists for example in Aa2-73 and Aa5-69:

Though the right limbs are here not 'snakes' but normal legs.

Searching for hanau glyphs with imbalance I cannot but notice how the semi-circular ear appears in for example the following glyphs:

Aa2-26 Aa2-73 Aa3-48 Aa4-8--9
Aa4-28 Aa4-36 Aa4-47 Aa4-55 Aa4-61
These are the first 12 hanau glyphs on side a. At (presumably) Aa4-28 the semi-circular ear moves from one side to the other. Between Aa4-61 and Aa5-62 a return movement occurs.
Aa5-62--63

The numbers (4 and 8) in Aa4-28 are 'cosmic', and between Aa4-61 and Aa5-62 there is an internal parallel starting from Aa4-63, the only one internal parallel with twice 10 = 20 glyphs:

Internal parallel texts in Tahua

1

Aa2-68--75 / Ab2-41--45

8

5

2

Aa3-6--15 / Ab2-34--40

10

7

3

Aa4-12--18 / Ab1-14--20

7

7

4

Aa4-63--72 / Ab5-1--10

10

10

5

Aa4-73--a5-35 / Ab7-12--b7-59

45

40+3+5

6

Aa5-50--53 / Ab7-75--78

4

4

7

Aa5-68--73 / Ab7-79--b8-1

6

7

8

Aa5-74--81 / Ab8-13--23

8

11

9

Ab3-1--29 / Ab5-11--35

29

25

10

Ab5-59--64 / Ab6-4--11

6

8

The sequence Ab5-1--10 arrives immediately to the right of the midpoint, as defined by line numbers on side b. Aa4-63--64 are at the midpoint, as defined by 100π glyphs:

If we count including Aa1-1 then Aa4-63 corresponds to 100π (251 + 63 = 314), if we count excludning Aa1-1 then Aa4-64 is needed to reach 100π.

We remember that Hb7-7--26 corresponds to the 20 glyphs which explain the difference between 648 and 200π on Large Santiago Tablet. The structure is 314 + 20 + 314, i.e. 20 is in the middle of the text on side b:

Hb1-1 -- Hb7-6 314 20 314
Aa1-1 -- Aa4-63 251 + 63 = 314 10 670 - 314 - 10 = 346
Ab5-1 -- Ab5-10 324 = 10 + 314 10 664 - 314 - 10 - 10 = 330

346 - 314 = 32 and 330 - 314 = 16.

In the middle of side a of H we found Ha6-106 etc:

Ha6-106

Ha6-107

Ha6-108

Ha6-109

Ha6-110

Ha6-111

Ha6-112

Ha6-113

In spite of the destroyed glyphs on H we may try to recreate the glyph number for Ha6-106. According to what I earlier have arrived at, there may once have been 24 (= 19 + 5 destroyed) glyphs before Ha6-106:

a1 50 50
a2 58 108
a3 52 160
a4 56 216
a5 59 275
a6-1 -- a6-106 19 + 5? + 1 = 25? 300

We can therefore try to add side a of H to the table:

Ha1-1 -- Ha6-19 + 5? 299 20 648? - 299 - 20 = 329 648?
Hb1-1 -- Hb7-6 314 20 314 648
Aa1-1 -- Aa4-63 251 + 63 = 314 10 670 - 314 - 10 = 346 670
Ab5-1 -- Ab5-10 10 + 314 = 324 10 664 - 324 - 10 = 330 664

329 is quite close to 330. If we add 15 to 299 we reach 314, and 329 - 15 = 314. The glyph sequence which we reach by this manipulation is Ha6-121 etc:

Ha6-121 Ha6-122 Ha6-123 Ha6-124 Ha6-125 Ha6-126
Ha6-127 Ha6-128 Ha6-129 Ha6-130 Ha6-131 Ha6-132
Ha6-133 Ha6-134 Ha6-135 Ha6-136 Ha6-137 Ha6-138
Aa2-1 is parallel with Ha6-142, which indicates a 'break' after Ha6-141. We have learnt that the lines in A seems to be constructed as semi-separate wholes.
Ha6-139 Ha6-140 Ha6-141

Ha6-121 -- 141 are 21 glyphs, one more than expected, which suggests that the searched for midsequence with 20 glyphs should be Ha6-122 -- 141. Presumably the parallel to Pa5-68 should have 2 glyphs, not 1 as guessed earlier:

...

 

...

 

Ha6-101 Ha6-102 Ha6-103 Ha6-104 Ha6-105
Pa5-67 Pa5-68 Pa5-69 Pa5-70 Pa5-71 Pa5-72

We can now adjust the numbers, step by step according to the above:

1 Ha1-1 -- Ha6-19 + 5? 299 20 648? - 299 - 20 = 329
2 Ha1-1 -- Ha6-19 + 6 (?) 300 20 648? - 300 - 20 = 328
3 Ha1-1 -- Ha6-19 + 6 (?) + 14 314 20 648? - 314 - 20 = 314
Hb1-1 -- Hb7-6 314 20 314

We have arrived at two alternatives. The first alternative is the old one - to fix the 20 glyphs as Ha6-106--125 (with a nice number of glyphs, 300, arriving before the 20):

Ha6-106

Ha6-107

Ha6-108

Ha6-109

Ha6-110

Ha6-111

Ha6-112

Ha6-113

7 glyphs (Ha6-114--120)
Ha6-121 Ha6-122 Ha6-123 Ha6-124 Ha6-125
Aa1-49 Aa1-50 Aa1-51 Aa1-52 Aa1-53 Aa1-54 Aa1-55 Aa1-56
7 glyphs (Aa1-57--63)
Aa1-64 Aa1-65 Aa1-66 Aa1-67 Aa1-68

The other (new) alternative is to adjust 300 to 314 to reach a symmetry with side b. Then the 20 glyphs will be Ha6-120--139:

Ha6-120 Ha6-121 Ha6-122 Ha6-123 Ha6-124 Ha6-125 Ha6-126 Ha6-127
7 glyphs (Ha6-128--134)
Ha6-135 Ha6-136 Ha6-137 Ha6-138 Ha6-139

Ha6-120 and Ha6-139 clearly define 18 glyphs between them. No such evidence can be seen in the old alternative. In Tahua we can assemble the following parallel glyphs:

Aa1-63 Aa1-64 Aa1-65 Aa1-66 Aa1-67 Aa1-68 Aa1-69 Aa1-70
4 glyphs (Aa1-71--74)
Aa1-75 Aa1-76 Aa1-77 Aa1-78 Aa1-79

In Aa1-79 the little 'bird' is looking forward, not backwards as in Ha6-139, but Aa1-63 and Aa1-79 together indicate (as in H) a set of glyphs.

However, where in H there are 7 glyphs (Ha6-128--134) there are only 4 (Aa1-71--74) in A:

Ha6-128 Ha6-129 Ha6-130 Ha6-131 Ha6-132 Ha6-133 Ha6-134
Aa1-71 Aa1-72 Aa1-73 Aa1-74

Instead of a group of 20 glyphs Tahua has only 17 glyphs, a number indicating that the set of glyphs in A is not defined by endpoints at Aa1-63 and Aa1-74 (at least on of them must be wrong).

But this fact does not preclude arranging the glyphs in H with 20 central glyphs defined as Ha6-120--139. The glyph label numbers and the glyph numbers counted from the beginning of side a can be reconstructed like this, (examples):

Ha6-106

Ha6-110

Ha6-111 Ha6-114 Ha6-116 Ha6-125
19 + 6 (?) + 6 → *Ha6-31 *Ha6-35 *Ha6-36 *Ha6-39 *Ha6-41 *Ha6-50
275 + 31 (?) = *306 *310 *311 *314 *316 *325

Ha6-101 will be the *301st glyph on side a with a reconstructed line number -25:

- -
Aa1-13 Aa1-14 Aa1-15
kua tuu marai i tona ohoga - ki te ariki
...  ...  ...
Ha6-101 Ha6-102 Ha6-103 Ha6-104 Ha6-105
*Ha6-22 *Ha6-23 *Ha6-24 *Ha6-25 *Ha6-26 *Ha6-27 *Ha6-28 *Ha6-29
*298 *299 *300 *301 *302 *303 *304 *305
Pa5-67 Pa5-68 Pa5-69 Pa5-70 Pa5-71 Pa5-72
This sequence of glyphs does not appear in Q

The glyph which in Tahua is parallel to Ha6-114 (the π glyph) is Aa1-57:

Aa1-57
ko te kura

We can read Aa1-57 as a fully grown person, a 'noon' person.

Kura

1. Also: poukura, the short, thin, multicoloured feathers of chickens and other birds. 2. The best of something, choice. Vanaga.

Tutui kura, shawl. Kurakura, fair, light. Hakakurakura, to make to blush. P Pau.: kurakura, red, violet. Mgv.: kurakura, red, yellow, scarlet. Mq.: uáuá, red, ruddy. Ta.: uraura, red. Churchill.

The new alternative of locating the 20 glyphs (on side a of H), with reconstructed numbers, is:

Ha6-120 Ha6-121 Ha6-122 Ha6-123 Ha6-124 Ha6-125 Ha6-126 Ha6-127
*Ha6-45 *Ha6-46 *Ha6-47 *Ha6-48 *Ha6-49 *Ha6-50 *Ha6-51 *Ha6-52
*320 *321 *322 *323 *324 *325 *326 *327
7 glyphs (Ha6-128--134)
Ha6-135 Ha6-136 Ha6-137 Ha6-138 Ha6-139
*Ha6-60 *Ha6-61 *Ha6-62 *Ha6-63 *Ha6-64
*335 *336 *337 *338 *339

Earlier I have reconstructed the number of glyphs in line Ha6 as '69?', now we may rather confidently adjust it to '*70 (?)':

a1 50 50
a2 58 108
a3 52 160
a4 56 216
a5 59 275
a6 *70 (?) *345 (?)

Our gradually improved table comparing the sides of H with the sides of A can be updated into:

Ha1-1 -- Ha6-119 (?) 314 20 314 648?
Hb1-1 -- Hb7-6 314 20 314 648
Aa1-1 -- Aa4-63 251 + 63 = 314 10 670 - 314 - 10 = 346 670
Ab5-1 -- Ab5-10 10 + 314 = 324 10 664 - 324 - 10 = 330 664