TRANSLATIONS

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It is reasonable to imagine the creator of the Tahua text to have juggled numbers of glyphs in order to make a 'statement' in form of distance between midsummer solstice (Aa4-59) and te pito (Ab8-43):

    

We should check this assumption now. I take the opportunity to include the number tables for distances between glyphs as a page to be reached via:

texts / Tahua o / next page / next page

Furthermore, I use our question as an example of how the tables works:

Sums of glyphs in consecutive lines:
+ 1 2 3 4 5 6 7 8
b1 82 167 244 324 404 496 580
664
b2 85 162 242 322 414 498
582
672
b3 77 157 237 329 413
497
587 672
b4 80 160 252 336
420
510 595 671
b5 80 172 256
340
430 515 591 673
b6 92 176
260
350 435 511 593 676
b7 84
168
258 343 419 501 584 668
b8
84
174 259 335 417 500 584 669
a1 90 175 251 333 416 500 585
670
a2 85 161 243 326 410 495
580
662
a3 76 158 241 325 410
495
577 662
a4 82 165 249 334
419
501 586 663
a5 83 167 252
337
419 504 581 661
a6 84 169
254
336 421 498 578 658
a7 85
170
252 337 414 494 574 666
a8
85
167 252 329 409 489 581 665
sum 1334 * 2 * 3 * 4 * 5 * 6 * 7 * 8
Sums of glyphs in consecutive lines counted beyond 8 lines:
+ 9 10 11 12 13 14 15 16
b1 754 839 915 997 1080 1164 1249
1334
b2 757 833 915 998 1082 1167
1252
1334
b3 748 830 913 997 1082
1167
1249 1334
b4 753 836 920 1005
1090
1172 1257 1334
b5 756 840 925
1010
1092 1177 1254 1334
b6 760 845
930
1012 1097 1174 1254 1334
b7 753
838
920 1005 1082 1162 1242 1334
b8
754
836 921 998 1078 1158 1250 1334
a1 752 837 914 994 1074 1166 1250
1334
a2 747 824 904 984 1076 1160
1244
1334
a3 739 819 899 991 1075
1159
1249 1334
a4 743 823 915 999
1083
1173 1258 1334
a5 741 833 917
1001
1091 1176 1252 1334
a6 750 834
918
1008 1093 1169 1251 1334
a7 750
834
924 1009 1085 1167 1250 1334
a8
749
839 924 1000 1082 1165 1249 1334
The sums from beginning of each line and up to the end of the page
 appear in rectangles.

To count the glyphs from Aa4-59 to Ab8-43, for example, we search for a4 in the bottom table (because b8 lies more than 8 lines ahead of a4).

The first number in line a4 is 743 which is the sum of the number of glyphs in all the lines from a4 up to and including line b4. To get the sum from Aa4-1 up to and including line b7 we take 999.

Next we adjust 999 by adding 43 (the ordinal number of Ab8-43) = 1042. Then we should reduce 1042 by 59 (the ordinal number of Aa4-59) = 983.

(The distance measured in number of glyphs between Aa4-59 and Ab8-43 is 1 less, i.e. 982.)

The results may be summarized like this:

984 from Aa4-59 up to and including Ab8-43
983 from Aa4-59 to Ab8-43
982 between Aa4-59 and Ab8-43

The results at first do not seem to be very encouraging: 982 = 2 * 491, 983 is a prime number and 984 = 24 * 41.

If we count with Aa4-60 instead, the numbers will be 983, 982 and 981 (= 9 * 109). If we count with Aa4-58 instead, the numbers will be 985 (= 5 * 197), 984 and 983.

If we count with Ab8-42 instead, the new distances will be 983, 982, 981 (Aa4-59), 982, 981, 980 (Aa4-60) respectively 984, 983, 982 (Aa4-58).

The only new number is 980 (between Aa4-60 and Ab8-42) = 2 * 2 * 5 * 7 * 7 =  28 * 35.

28 is the number of moon-is-shining nights in a month and 35 is the lunar month we have reconstructed as 420 / 12.

The method used gives a series of possible results (980, 981, 982, 983, 984, 985) depending on how we measure. It may therefore be a coincidence when we imagine us see a 'cosmic' number (980).

We must not forget to measure the other way around the circuit:

1334 - 980 = 354 = 2 * 3 * 59 = 6 * 59

That does it! Another 'cosmic' result appears: 59 is the number of nights in a 'true' double month (we include also the nights when moon is invisible), while 6 is the number of such 'true' months which are possible to make room for inside a year:

6 * 59 = 354 and 7 * 59 = 413

We have arrived at the conclusion that there is an intended length between Aa4-60 and Ab8-42:

28 * 35 = 980 6 * 59 = 354
Aa4-60 counted between (exclusive) Ab8-42 counted inclusive Aa4-60
e pare tuu ki te ragi huki hoi e pare tuu ki te ragi
980 + 354 = 1334

However, it may be that we should shift the glyphs one step to the right:

28 * 35 = 980 6 * 59 = 354
Aa4-61 counted between (exclusive) Ab8-43 counted inclusive Aa4-61
e hanau o te pito motu e hanau
980 + 354 = 1334

I think this is a better solution. We have the 'navel point' in the center, as it should be. Furthermore,  e hanau presumably means a point of birth.

If we move ahead from Ab8-43 up to and including Aa4-61 I guess it means to move from the center (mother earth) to the point of birth.

The alternative path from (just after) birth is leading up to the point of death (back to earth).

Considering the form of Ab8-43 the alternative path is probably the main one: Given that GD56 (hanau) describes 'birth' (which I earlier have guessed), then logic implies that the upsided down 'legs' of GD56, placed at the top of Ab8-43, means the opposite, viz. 'death'.

The alternative path (painted red above) is 'life', the path between birth and death.