The last part of line Cb3 contains the June solstice:
The 'flower' in June 21 is wilting. It has 6 petals and the idea is probably to illustrate the final of old Sun. A solstice means he no longer can move. We can then perceive how the 4 quarters of the Gregorian year are depicted:
Only the 92 days from March 21 (80) to June 21 (172) are characterized as a time with Sun present (north of the equator). The rest of the year, 365 - 92 = 273 days, equals the day number for September 30. This means the 4th quarter is similar to the 2nd quarter. Cb3-19 has been given a design which is similar to that of Cb3-17. But instead of a perfect oval (egg-form) for the face of Sun there is an irregular diamond outline which should represent the opposite - a time of inactive earth. There are 6 'petals' in Cb3-17, but 7 'feathers' in Cb3-19. 92 + 92 = 184. The 1st and 3rd quarters will together cover 181 days. March 21 is day 80 and the 3rd quarter will therefore have 181 - 80 = 101 days. September 30 (273) - June 21 (172) = 101:
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