TRANSLATIONS

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The previous page was written before I made the long detour around the world of G. Looking at it again it does not seem to be very good. What was established? Not much as regards the location of Ha12-4--5:

Ha12-1 Ha12-2 Ha12-3 Ha12-4 (631) Ha12-5

631 is 100 more than 531, which could be a sign:

290
Ha5-22 Ha5-23 Ha5-24 (240) Ha10-29 (531) Ha10-30 Ha10-31 Ha10-32
80 177 = 6 * 29.5 178

In Tahua (with an assumed 2 glyphs per day) glyph number 531 would correspond to Te Pou (18 * 29.5 = 531):

The ordinal numbers have been counted from Gb8-30 respectively from Ab8-44.
Te Pei

8 * 29.5 = 236

Gb1-6 (236) Aa6-12 Aa6-13 Aa6-14 Aa6-15 (472)
Te Pou

9 * 29.5 = 265.5

Gb2-10 (266) Aa6-70 Aa6-71 Aa6-72 Aa6-73 (531)
Hatinga Te Kohe

12 * 29.5 = 354

Gb4-33 (354) Aa8-79 Aa8-80 Aa8-81 Aa8-82 (708)

To rely on Tahua is not advisable though, we know it not. Instead, we should first of all try to use the text of H itself. Ha5-24 (with ordinal number 240 = 10 * 24) is of prime interest, it surely indicates a cardinal point:

290
Ha5-22 Ha5-23 Ha5-24 (240) Ha10-29 (531) Ha10-30 Ha10-31 Ha10-32
80 177 = 6 * 29.5 178

If it marks midsummer, which has been stated earlier with some confidence, then we can understand why sun is fading away half a year later.

240 is equal not only to 4 * 60 but also to 3 * 80. If we add 120 we will have 360 = 6 * 60 = 80 * 4½. To work with 3 rather than with 4 seems to be more correct. We must search for midwinter some 100 days = 300 glyphs earlier than at Ha1-1.

Experience from G have taught us that winter solstice should be 64 days before the beginning of the text on side a. 64 = 8 * 8 could, though, very well be 100 = 10 * 10 according to H. 300 can be divided by 3, but not 64.

648 glyphs on each side of H is equal to 216 days (given 3 glyphs per day). Counting backwards on side b we find a series of sums: 648, 597, 544 ... and we need a number equal to 648 - 300 = 348:

a1 50 50 b1 *51 (?) 51
a2 58 108 b2 48 99
a3 52 160 b3 47 146
a4 56 216 b4 51 197
a5 59 275 b5 57 254
a6 *69? 344 b6 54 308
a7 *51? 395 b7 50 358
a8 *54? 449 b8 *54 (?) 412
a9 *53? 502 b9 65 477
a10 *67? 569 b10 67 544
a11 *58? 627 b11 53 597
a12 *21? 648 b12 *51? 648
sum *648? sum *648?

The searched for glyph should be Hb7-40:

Hb7-32 Hb7-33 Hb7-34 Hb7-35 Hb7-36 Hb7-37
330 331
Hb7-38 Hb7-39 Hb7-40 (996) Hb7-41 Hb7-42 Hb7-43
332 333

From Hb7-40 to Ha5-24 there  are (1296 - 996) + 240 = 540 glyphs , equal to 180 days.

332 + 100 = 432 = 80 + 252 (= 7 * 36) + 100. 180 = 5 * 36, and 432 = 12 * 36.

Yet, we have seeen, 80 possibly is 2 + 78:

 
Ha1-1 Ha1-2 Ha1-3 Ha1-4 Ha1-5 Ha1-6
1 2
Ha1-7 Ha1-8 Ha1-9 Ha1-10 Ha1-11 Ha1-12
3 4

A 'midnight' henua at Ha1-6 is followed by a rising fish in Ha1-8. In between is honui with mea ke at right. But comparison with the night calendar in Tahua gives an indication that indeed Ha1-1 presumably is the first glyph of the new day, because Aa1-43 seems to be the 2nd glyph after midnight:

Aa1-37 Aa1-38 Aa1-39 Aa1-40 Aa1-41
Aa1-42 Aa1-43 Aa1-44 Aa1-45
Aa1-46 Aa1-47 Aa1-48

Maybe the hole in honui (Ha1-7) represents a kind of 'portal' for the newborn sun to enter through. Metoro said raaraa (central ceremonial ground) at Aa1-43, and toraaraa is to raise up:

 
Raa

Sun; day; i te raá nei, today; raá îka, good day for fishing. Vanaga.

1. Sun. 2. Day. 3. Time. 4. Name of sub-tribe. Fischer.

Te manu i te raá = comet. Barthel.

'... The substitution of the sun for the sail, both of which are called ra or raa in Polynesia, is a remarkable feature in Easter Island art... ' Heyerdahl 3.

1. The sun; raa ea mai, raa puneki, sunrise; raa tini, raa toa, noon. P Mgv., Ta.: ra, the sun. Mq.: a, id. 2. Day, date; a raa nei a, to-day, now; raa i mua, day before. P Mgv., Ta.: ra, a day. Mq.: a, id. Churchill.

'... The chief thus makes his appearance at Lakeba from the sea, as a stranger to the land. Disembarking at the capital village of Tubou, he is led first to the chiefly house (vale levu) and next day to the central ceremonial ground (raaraa) of the island ...' (Islands of History)

Ta.: toraaraa, to raise up. Churchill 2.

The situation is similar at the beginning of 'October' (Te Pei), where instead of a flat earth surface the location is in the deep water. Both places must be 'enlightened' by way of raising up 'fire', sun respectively Sirius. A vertical wooden pole (toko, pou) symbolizes both the direction up and the potential of fire.

In the chilly early mornings, if such existed on Easter Island, a fire would feel good, equally so in the evening when people came together to eat, tell stories, and dance.

Even if the climate of Easter Island did not necessitate a fire in the morning, the inhabitants seem to have greeted the rising sun with fires.

Next there is the observation of a glyph difference of 231 (= 531 - 300) between Ha1-7 and Ha5-22:

 

230
Ha1-7 (1) Ha5-22 (232)
2⅓ 76⅔ 77⅓

Ha1-7 is the first glyph in day 3 and Ha5-22 is the first glyph in day 78. Maybe honui glyphs refer to the birth of a new 'day'.

78 - 3 = 75, and 3 * 75 = 225 = 15 * 15. There is a square between them. 15 is the number of the full moon night and it could allude to a 'full sun'.

We realize that the same argument possibly could be used to explain why there are 230 glyphs on side a of G (including Gb8-30, where 8 * 30 = 240, also in a way parallel with the ordinal number of Ha5-24).

 
Ga8-16 Ga8-17 Ga8-18 Ga8-19 Ga8-20
Ga8-21 (225) Ga8-22 Ga8-23 Ga8-24 Ga8-25
Ga8-26 (230) Gb1-1 Gb1-2 Gb1-3 Gb1-4

The hole in Gb1-3 (233) seems to be congruent with the hole in Ha5-22 (232 from Ha1-7), especially if we begin counting from Ga1-1.

Ha1-7 is the first glyph in day 3, and there are 3 days between Ga8-26 and Gb1-4 (which obviously is connected forward with the similar glyph at Gb1-12).

And then we must assign Ha5-22 its proper number, which is 232 + 6 = 238:

 
Ha5-22 (238) Ha5-23 Ha5-24 (240) Ha5-25 Ha5-26 Ha5-27

In other words, 15 * 15 = 225 points at Ga8-21, where 8 * 21 = 168. And from Ga8-21 to Gb1-4 there are 9 days, a sign that old spring sun is vanishing. Which glyph is number 225 in H? 238 - 225 = 13, and it must be Ha5-9. 'Fire' and 9 together ought to mean that the fire has gone out. Certainly somebody seems to be going away at the beginning of line Ha5:

Ha5-1 Ha5-2 Ha5-3 Ha5-4 Ha5-5 Ha5-6
73 74
Ha5-7 Ha5-8 Ha5-9 (225) Ha5-10 Ha5-11 Ha5-12
75 76
Ha5-13 Ha5-14 Ha5-15 Ha5-16 Ha5-17 (233) Ha5-18
77 78
Ha5-19 Ha5-20 (236) Ha5-21 Ha5-22 Ha5-23 Ha5-24 (240)
79 80

Possibly we have to look ever earlier for the beginning of the process, because in G we have 45 days for it.

183 43 65 178
Ga5-10 (121) Ga6-24 (165) Gb6-26 (409)
228 = 12 * 19 244 = 4 * 61

We also should notice 178 days from the beginning of side b to winter solstice at Gb6-26. It is quite as in 178 days from Ha1-1:

Ha10-30 Ha10-31 Ha10-32 (534) Ha10-33 Ha10-34 Ha10-35 (537)
178 179

We can establish with a rather high degree of confidence that Ha10-35, the last glyph in day 179, is equivalent with Gb6-26, at day 179 counting from the beginning of side b.

Furthermore, we must take the opportunity of comparing Ha5-6 with Ga7-5:

31
Ga7-5 Ga7-6 Ga7-7 (177) Ga7-8 Ga7-9 Ga7-10

The very last henua period before sun has disappeared totally and been replaced by tama (Ga7-11) is beginning with what looks like ihe tau flying away. A square is completed, it seems, with Ga7-7 (where 7 * 7 = 49 and only 'one more', as in Ga7-11, is needed to reach a zero day for 'fire').

177 = 6 * 29.5 is another sign of the final. Henua ora has 8 feathers on each side. Ha5-13 has 3 feathers on each side, and we need those 100 days from the end of side b to reach the intended day number 6 * 29.5 = 177

Surely we are on secure ground so far. And we have established as 'fact' that the 31 henua periods end at midsummer.

31 + 26 = 57 glyphs come before the first glyph in the first henua period. We can add 64 from the end of side b: 64 + 57 = 121 = 11 * 11, a 'child' square.

At 181 (Ga7-11) another child enters. The henua calendar covers 181 - 57 = 124 = 12 * 12 days, another square.

11 * 11 + 12 * 12 = 265, and then Te Pou will arrive.

If we add 13 * 13 = 169, we will reach to 434, suspiciously close to 432 (days in H).

Moreover, I once discovered that 10 * 10 + 11 * 11 + 12 * 12 = 365 = 13 * 13 + 14 * 14. Certainly the Easter Islanders knew it too, a natural expansion of the formula for the Egyptian triangle: 3 * 3 + 4 * 4 = 5 * 5.

For measuring the 'earth of time' we have to change 25 into 365.