Next page in the series from '531
+ 400 + 365 = 1296':
From the names and
the ordered structure of the 12 years of the Moriori fishermen,
who once inhabited Chatham Islands, I assumed their months were
named and ordered similarly.
Then a search for a 'season
of hua poporo' (corresponding to To
Whanga-poroporo,
the 6th year in the calendar
of the Moriori) led to the discovery
of an earlier not perceived structure, where in G a 'season of poporo' apparently
arrives beyond 184 days of spring and where 200 days are
following the poporo season at the end of side b:
182
86
Gb8-30
(1)
Ga7-14
Ga7-15
(185)
Gb2-16
(272)
184
88
198
Gb2-17
Gb8-30
(472)
200
272
glyphs (presumably days) can be interpreted as 2 *
72 (= 144). 272 is also = 4 * 68 = 4
* (32 + 36).
184 + 200 = 384 = 2 * 192,
and the central 88 glyphs where hua poporo is
an essential ingredient evidently represents the
season of high summer. The long neck in Ga7-15 could
indicate 'high'.
88
can be read in various ways, but what possibly was
meant is the addition 29 + 59. Maybe 88 means
the 'dark cloth' which hides the mysterious process
of regeneration? An 'overlapping' between Spring Sun
and Autumn Moon perhaps is indicated by the numbers:
88 + 200 = 288 = 2 * 144.
One
way to use the new ideas is to guess that
those 400 glyphs which follow ariki in
Ha10-29 should be divided by 2 in order to find the
number of days:
393
Ha10-30
Ha10-31
Ha10-32
Hb6-26
Hb6-27
Hb6-28
Hb6-29
400 / 2 = 200 days
It is
then reasonable to also divide the glyphs up to ariki
by 2 to find the number of days. Instead of 18 *
29.5 days we will then have 9 * 29.5 = 265½ days, which appears to
be more in harmony with how many days in a year Sun can be expected
to 'rule'.
236
293
Ha5-21 (237)
Ha10-29 (531)
4 * 29.5 days
5 * 29.5 days
Division by 2 leads,
however, to also another possible alternative than 265½ days:
114
296
Ha3-11
(119)
Ha3-12
Ha5-19
Ha5-20
(236)
Ha10-31
Ha10-32
60 = 120 / 2
57
236 / 2 = 118
148
267 = 118 + 149
208 days (= 8 * 26 = 60 + 148)
I think it has now been
'proven' that we must
divide the number of
glyphs by 2 when
considering the meaning
of pare in H. Sun
rules according to the
new alternative during 8
* 26 = 208 days and he
arrives in day number 60
counted from the
beginning of side a.
Ha10-30 is the
last glyph of his rule and 10 * 30 = 300 is another measure
relating to Sun, but a measure of no use (it seems) when
discussing pare. Furthermore, I have now decided to add Ha5-19
to the few pare glyphs in my catalogue.
The equation 60
+ 148 = 208 may, though, say that Sun rules from the first
glyph on side a and up to (and including) the double Rei
in Ha3-12 (where 3 * 12 = 36). If we add 64 days from winter
solstice to the end of side b it becomes 64 + 60 = 124 = 4 *
31, i.e. he rules during 4 months. Then comes 58 days which
could belong to the 'Spring Serpent' or some other
uncultivated creature. And when the 'snake' has been
'decapitated' (he does
not survive to day 59), order is restored and there are 148
further days to the end of Sun's rule.
124 + 148 = 272 - the
same number as at the end of the 'hua poporo season'
in G. Gb2-16 apparently says '216' which is one of the key
numbers in rongorongo (cfr at mea ke):
144
12 * 12
168
12 * 14
216
12 * 18
192
12 * 16
360 = 12 * 30
For instance is
1296 the number of glyphs in H and 1296 = 6 * 216 = 12 *
108. And in G glyph number 408 = 12 * (18 + 16) = 216 + 192
refers to the last day of the old year:
Gb6-25
(408)
Gb6-26
As to the
structures of Q and H in comparison with G we will now to
take a quick look in order to see if
the hua poporo glyphs
can help us to more definite solutions.
These are the 15
hua poporo glyphs which I have assembled from the text of H:
Ha9-8
*Ha11-46
*Hb1-32
*Hb1-48
*Hb1-59
Hb2-4
Hb2-8
Hb2-13
Hb2-34
Hb4-28
*Hb8-49
Hb9-54
Hb10-34
Hb11-24
Hb12-32
It is easy to find where the hua poporo glyphs in H are
concentrated, because half of them appear in glyph lines
b1-b2:
*Hb1-32
*Hb1-48
*Hb1-59
Hb2-4
Hb2-8
Hb2-13
Hb2-34
They are
located among the 400 glyphs which I have guessed may
represent 200 days of Autumn Moon:
393
Ha10-30
Ha10-31
Ha10-32
Hb6-26
Hb6-27
Hb6-28
Hb6-29
400 / 2 = 200 days
We can upgrade the
distributional pattern of the 15 hua poporo glyphs into a
structure with 2 + 10 + 3 glyphs based on where they appear:
Ha9-8
*Ha11-46
*Hb1-32
*Hb1-48
*Hb1-59
Hb2-4
Hb2-8
Hb2-13
Hb2-34
Hb4-28
*Hb8-49
Hb9-54
Hb10-34
Hb11-24
Hb12-32
The
redmarked ones are among the 400, but the last 5
of the 15 are among the 365 last
glyphs on side b. But we had better take a closer look
if there really are 365 glyphs beyond those 400.
Both Barthel
and Fischer indicate that there seems to be one
destroyed glyph at the end of the text, but I have
counted with 2.
If there is only 1 missing glyph
at the end of side b the
suggested last calendar cycle could be 364 days long
instead of 365 days. But then the total number of glyphs
cannot be 1296. We need an
extra page to consider the alternatives.
The number
of glyphs on side a of H can be considered to be 579
(580?), to be 648 (the sum of redmarked 627 and 21 in
the table below), or to be 666 (= 648 + 18):
a1
50
50
burnt area could have
contained the number of
glyphs below
50
b1
*51 (?)
51
a2
58
108
108
b2
48
99
a3
52
160
160
b3
47
146
a4
56
216
216
b4
51
197
a5
59
275
275
b5
57
254
a6
64
339
*5
344
b6
54
308
a7
48
387
*3
395
b7
50
358
a8
46
433
*8
449
b8
*54 (?)
412
a9
40
473
*13
502
b9
65
477
a10
49
522
*18
569
b10
67
544
a11
36
558
*22
627
b11
53
597
a12
*21 (?)
579
*18 (?)
666
b12
*51 (?)
648
sum
*666 (?)
sum
*648 (?)
It has been shown that the burnt
area probably was there already when
the creator carved his glyphs on the
tablet (cfr at hahe), but that anyhow 648 (= 6 *
108) is a good alternative.
The visible glyphs on side a
- including the vacant space for *Ha12-19
- sum
up to the odd number 579, and maybe
we should think '+ one more' as when
we count to 472 glyphs for the text
of G although there are only 471 glyphs
on the tablet. 580 = 20 * 29.
However, the burnt area covers also
a space at the end of line a12 where
an estimated number of 18 glyphs can
be imagined. 666 (= 6 * 111) is
therefore also a possible
alternative.
But neither 579 nor 580 is divisible
by 6.
On side b there is no burnt area.
Yet, there are glyphs which are
totally missing in line b1. There
are 3 fully
visible glyphs followed by 24
totally or partially invisible ones:
Hb1-1
Hb1-2
Hb1-3
Hb1-4
Hb1-5
Hb1-6
...
...
...
...
Hb1-7
Hb1-8
*Hb1-9
*Hb1-10
*Hb1-11
*Hb1-12
...
...
*Hb1-13
*Hb1-14
*Hb1-15
*Hb1-16
*Hb1-17
*Hb1-18
...
...
...
...
*Hb1-19
*Hb1-20
*Hb1-21
*Hb1-22
*Hb1-23
*Hb1-24
*Hb1-25
*Hb1-26
*Hb1-27
*Hb1-28
*Hb1-29
*Hb1-30
*Hb1-31
*Hb1-32
Then, suddenly, the glyphs are fully
visible again. I guess those 24 more
or less invisible glyphs are meant
to be a sign. The
redmarked 16 glyphs above are close
to the 15 respectively 17 parallel
ones in P and Q:
tablet
number of glyphs
H
ca 16
P
15
Q
17
The picture of glyph line Hb1 in
Barthel does not in any way suggest 16 must be
wrong. Therefore we
should calculate with *32 + 19
(*Hb1-33--51) = *51 glyphs in
line Hb1 (while remembering to think
± 1).
But we have two more question marks
to consider,
viz. in lines Hb8 and Hb12. There is
a very special
absent glyph in line Hb8 and it was
discussed at hakaturou. The
parallel text in P has here an unusual sign
which I have decided to name
pito
(navel):
...
Hb8-15
*Hb8-16
*Hb8-17
*Hb8-18
*Hb8-19
*Hb8-20
*Hb8-21
Pb9-32
Pb9-33
Pb9-34
Pb9-35
Pb9-36
Pb9-37
The creator of H has probably left a
vacancy (clearly seen in the picture
of the line in Barthel) for *Hb8-16. I have counted
the vacant place among the *54 in
the table above.
The last question mark on side b
needs a more detailed description.
The uncertainty comes at the very
end of line Hb12:
Hb12-29
Hb12-30
Hb12-31
Hb12-32 (629)
Hb12-33
Hb12-34
Hb12-35
Hb12-36 (633)
Hb12-37
Hb12-38
Hb12-39
Hb12-40 (637)
Hb12-41
Hb12-42
Hb12-43
Hb12-44
Hb12-45
Hb12-46 (643)
...
...
Hb12-47
Hb12-48
Hb12-49
*Hb12-50
*Hb12-51
(648)
Maybe
*Hb12-51 is a glyph which should be only imagined - like
*Hb8-16. Or maybe we should accept that *Hb12-50 (where
12 * 50 = 600) is the last glyph of the text.
In the
latter case we can still reach 648 by increasing 51 to
52 in line b1:
a1
50
50
burnt area could have
contained the number of
glyphs below
50
b1
*52 (?)
52
a2
58
108
108
b2
48
100
a3
52
160
160
b3
47
147
a4
56
216
216
b4
51
198
a5
59
275
275
b5
57
255
a6
64
339
*5
344
b6
54
309
a7
48
387
*3
395
b7
50
359
a8
46
433
*8
449
b8
*54 (?)
413
a9
40
473
*13
502
b9
65
478
a10
49
522
*18
569
b10
67
545
a11
36
558
*22
627
b11
53
598
a12
*21 (?)
579
*18 (?)
666
b12
*50 (?)
648
sum
*666 (?)
sum
*648 (?)
And 52 (b1) + 48 (b2) = 100 seems to
be equally good as 99.
413 = 14 *
29.5 instead of 412 for lines b1-b8 is better than 412. But then
648 - 413 = 235 suggests we should count also with
*Hb12-51 in order to reach 236 (= 8 * 29.5). That
decides it, I think, because 649 = 22 * 29.5 (and 22
suggests a full cycle because of the formula 22 / 7 = π).
The ordinal
number (counted from Hb1-1) of the glyphs at the end of
line Hb12 will then be as follows:
Hb12-29
Hb12-30
Hb12-31
Hb12-32 (630)
Hb12-33
Hb12-34
Hb12-35
Hb12-36 (634)
Hb12-37
Hb12-38
Hb12-39
Hb12-40 (638)
Hb12-41
Hb12-42
Hb12-43
Hb12-44
Hb12-45
Hb12-46 (644)
...
...
Hb12-47
Hb12-48
Hb12-49
*Hb12-50
*Hb12-51
(649)
In P, where all the glyphs
are visible, the sums are
599 (side a) respectively
559 (side b). It could
indicate a wish to end with
9 (here 99 respectively 59).
Side a of G has 229 glyphs
(excluding Gb8-30).
The last
visible glyph in H is Hb12-49, where 49 once again
appears (in addition to in 649). Possibly it means a
'square of 7' is finished. 12 * 49 = 588 (= 300 + 288)
and 6 * 49 = 294 (the final day before 10 * 29.5 = a
'zero' day is reached).
I decide to
change the tablet into:
a1
50
50
burnt area could have
contained the number of
glyphs below
50
b1
*52 (?)
52
a2
58
108
108
b2
48
100
a3
52
160
160
b3
47
147
a4
56
216
216
b4
51
198
a5
59
275
275
b5
57
255
a6
64
339
*5
344
b6
54
309
a7
48
387
*3
395
b7
50
359
a8
46
433
*8
449
b8
*54 (?)
413
a9
40
473
*13
502
b9
65
478
a10
49
522
*18
569
b10
67
545
a11
36
558
*22
627
b11
53
598
a12
*21 (?)
579
*18 (?)
666
b12
*50 (?)
648
sum
*666 (?)
sum
*648 (?)
Considering the sum of the glyphs on
side a and side b the following
alternatives are possible:
side a
side b
sum
579
648
1227
580
648
1228
648
648
1296
666
648
1314
Mea ke in Hb6-29 should be an
end glyph, and counting its ordinal
number from Hb1-1 it becomes 284:
393
Ha10-30
Ha10-31
Ha10-32
Hb6-26
Hb6-27
Hb6-28
Hb6-29
400 / 2 = 200 days
284 can be
read as 2 * 84 = 168 (or maybe as 28 'in a square'). Counting
from Hb1-1 seems to result in relevant signs. Both signs (168
respectively 28 and 4) should indicate that light is
ending.
Counting from Ha1-1 does also
give more or less acceptable
results:
side a
Hb6-29
sum
possible
explanation
579
284
863
500 + 4
580
284
864
8 * 8 * 8
648
284
932
288
666
284
694
364 + 200
None of these alternatives for side a
can be excluded.
If we should
count with 649 glyphs on side b, then there will be 649
- 284 = 365 glyphs beyond Hb6-29. If we should count
with only 50 glyphs in line Hb12 there will be 364
glyphs beyond Hb6-29.
