TRANSLATIONS

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We must take a look at the K structure arrived at earlier and see if any changes are needed:

1st calendar:

A

Ka2-1--6

6

9

10

B

Ka2-7--9

3

B

Ka2-10

1

C

Ka2-11--16

6

12

26

D

Ka2-17--22

6

E

Ka3-1--4

4

12

14

F

Ka3-5--8

4

G

Ka3-9--12

4

H

Ka3-13--14

2

2nd calendar:

1

Ka3-15

1

*73

1-6

Ka3-16--Ka4-14

spring

20

6-16

Ka4-15--Kb1-10

summer

26

*52

16-20

Kb1-11--*Kb2-14

*26

20-23

*Kb2-15--Kb3-8

humpback

12

26

27

24-28

Kb3-9--Kb4-6

rest of autumn

14

28

Kb4-7

winter solstice

1

28-29

Kb4-8--14

new year

7

 

First we have measured 75 from the 1st Rei (Ka2-10) up to and including the 3rd Rei (Kb1-11), followed by a guessed at 2nd group of 75 glyphs from Kb1-12 up to and including the absent *Kb5-11.

 

To present these new features of the structure it is necessary to combine the 1st and the 2nd calendar into a single calendar:

 

84

9

A

Ka2-1--6

6

9

10

B

Ka2-7--9

3

75

B

Ka2-10

1

C

Ka2-11--16

6

12

26

D

Ka2-17--22

6

E

Ka3-1--4

4

12

14

F

Ka3-5--8

4

G

Ka3-9--12

4

H

Ka3-13--14

2
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

 

 

 

59

 

 

 

 16-20 Kb1-12--*Kb2-14 *25
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-28 Kb3-9--Kb4-6 rest of autumn 14
28 Kb4-7 winter solstice 1
28-29 Kb4-8--14 new year 7

I have eliminated the black markings and put focus on the 3 Rei glyphs with red. Immediately we find new facts: 84 (= 3 * 28) emerges as the natural result of defining 75 glyphs. 84 = 75 + the 9 glyphs before the 1st Rei. And 59 (= 2 * 29.5) is the sum of the glyphs beyond the last Rei up to and including Kb4-14:

28
Kb4-6 Kb4-7 Kb4-8 Kb4-9
29
Kb4-10 Kb4-11 Kb4-12 Kb4-13 Kb4-14

Next we can add the beginning of side a:

*24 - Ka1-1--*Ka1-24 *24

84

9

A

Ka2-1--6

6

9

10

B

Ka2-7--9

3

75

B

Ka2-10

1

C

Ka2-11--16

6

12

26

D

Ka2-17--22

6

E

Ka3-1--4

4

12

14

F

Ka3-5--8

4

G

Ka3-9--12

4

H

Ka3-13--14

2
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

 

 

 

59

 

 

 

 16-20 Kb1-12--*Kb2-14 *25
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-28 Kb3-9--Kb4-6 rest of autumn 14
28 Kb4-7 winter solstice 1
28-29 Kb4-8--14 new year 7

If we add 84 with 24 (Ka1) we get 108 = 9 * 12 = 3 * 36.

Let us now mark the 3 viri glyps - and I will use black for that purpose. First we notice that Ka2-5 will destroy the unity earlier imagined for sequence A:

*24

-

Ka1-1--*Ka1-24

*24

84

9

A

Ka2-1--4

4

9

10
Ka2-5

1

Ka2-6

1

B

Ka2-7--9

3

75

B

Ka2-10

1

C

Ka2-11--16

6

12

26

D

Ka2-17--22

6

E

Ka3-1--4

4

12

14

F

Ka3-5--8

4

G

Ka3-9--12

4

H

Ka3-13--14

2
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

 

 

 

59

 

 

 

 16-20 Kb1-12--*Kb2-14 *25
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-28 Kb3-9--Kb4-6 rest of autumn 14
28 Kb4-7 winter solstice 1
28-29 Kb4-8--14 new year 7

The 1st viri (Kb1-14) - Ka2-5 is not the 1st but the 3rd viri - likewise will destroy the unity of 'summer':

*24

-

Ka1-1--*Ka1-24

*24

84

9

A

Ka2-1--4

4

9

10
Ka2-5

1

Ka2-6

1

B

Ka2-7--9

3

75

B

Ka2-10

1

C-H

Ka2-11--Ka3--14

 26
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

 

 

 

59

 

 

 

 16 Kb1-12--Kb1-13 2
16 Kb1-14 1
16-20 Kb1-15--*Kb2-14 *22
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-28 Kb3-9--Kb4-6 rest of autumn 14
28 Kb4-7 winter solstice 1
28-29 Kb4-8--14 new year 7

Here I have pressed together the sequences C-H into one line in the table, it is necessary to save space or we will be lost in the multitude of items. The 2nd viri (Kb4-6) is not so difficult to add. Therefore we will take one step more, to add lines at the end of the table to reach the end of side b:

*24

-

Ka1-1--*Ka1-24

*24

84

9

A

Ka2-1--4

4

9

10
Ka2-5

1

Ka2-6

1

B

Ka2-7--9

3

75

B

Ka2-10

1

C-H

Ka2-11--Ka3--14

 26
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

59

 16 Kb1-12--Kb1-13 2
16 Kb1-14 1
16-20 Kb1-15--*Kb2-14 *22
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-27 Kb3-9--Kb4-5 rest of autumn 13
28 Kb4-6 1
28 Kb4-7 winter solstice 1 1
28-29 Kb4-8--14 new year 7
25 4 30 Kb4-15--18    
12 31 Kb4-19--*Kb5-11    
1 31 *Kb5-12 winter solstice 2  
8 31 *Kb5-13--*Kb5-20    

Control: 34 + 84 + 59 + 25 = 192. I have written 'winter solstice 1' and 'winter solstice 2', and redmarked Kb4-7 together with *Kb5-12. Probably these two glyphs are important markers.

29 for the position of the 3rd viri (Ka2-5) is not explicitly mentioned in the table and we must rework its beginning:

*24

-

Ka1-1--*Ka1-24

*24

*28

 29

84

9

A

Ka2-1--4

4
Ka2-5

1

Ka2-6

1

 

   4

B

Ka2-7--9

3

    

75

B

Ka2-10

1

    

C-H

Ka2-11--Ka3--14

 26
1 Ka3-15 1 *73
1-6 Ka3-16--Ka4-14 spring 20
6-16 Ka4-15--Kb1-10 summer 26 *52
16 Kb1-11 1

59

 16 Kb1-12--Kb1-13 2
16 Kb1-14 1
16-20 Kb1-15--*Kb2-14 *22
20-23 *Kb2-15--Kb3-8 humpback 12 26 27
24-27 Kb3-9--Kb4-5 rest of autumn 13
28 Kb4-6 1
28 Kb4-7 winter solstice 1 1
28-29 Kb4-8--14 new year 7
25 4 30 Kb4-15--18    
12 31 Kb4-19--*Kb5-11    
1 31 *Kb5-12 winter solstice 2  
8 31 *Kb5-13--*Kb5-20    

It seems to be a hopeless task to include in a single table everything observed and imagined. Important is the result, though, that it is a single calendar and not two.