|
There are 3
viri glyphs and 3 Rei glyphs in the K text and they
seem to 'inhabit' different areas in the text:
 |
 |
 |
|
Ka2-10 |
Ka3-15 |
Kb1-11 |
|
1 |
28 |
75 |
 |
 |
 |
|
Kb1-14 |
Kb4-6 |
Ka2-5 |
|
3 |
51 |
29 |
While Rei
is in the 'light area', viri is in the 'dark
area'. With viri assumed to be 'without eyes' =
'blind' = 'in the dark' there cannot be any Rei
between Kb1-14 and Ka2-5. Likewise, there shouldn't be
any viri between Ka2-10 and Kb1-11.
This
explains why the glyph number measurements from Ka2-5 to
Kb1-14 and to Kb4-6 are meaningless. The number of
glyphs in the 'light area' (from Ka2-10 up to and
including Kb1-11) is a familiar 75, indicating we are on
the right path. (The 'light mauga' in Eb4-4 has
position 75, the end point of the 1st half.)
The 'dark
area', I have assumed in the table above, begins with
Kb1-12. If so, then the 'dark area' will have 192 - 75 =
117 glyphs, 2 before Kb1-14 and 4 beyond Ka2-5. 117 = 9
* 13. Probably, though, the 4 glyphs between Ka2-5 and
Ka2-10 should be regarded as outside the 'light' and
'dark areas':
 |
 |
 |
 |
|
|
Ka2-1 |
Ka2-2 |
Ka2-3 |
Ka2-4 |
Ka2-5 |
 |
 |
 |
 |
|
|
Ka2-6 |
Ka2-7 |
Ka2-8 |
Ka2-9 |
Ka2-10 |
Because then
the 'dark area' will have 84 + 29 = 28 + 28 + 28 + 29
glyphs (with Ka2-5 marking the end of the 'dark area').
|
There are 2 Rei on side a and 1 on side b, while the viri glyphs are (mirrorwise) 2 on side b and 1 on side a. I guess this is part of the general design.
Next question surely must be: The 2nd half in E ended with glyph number 150
- which glyph in K will have number 150?
The question can be answered by going backwards from Ka2-5, which is the 29th glyph from the beginning of side a.
192 - 150 = 42 glyphs must arrive beyond the searched for glyph number 150, and 29 are located at the beginning of side a.
42 - 29 = 13. Then we must reduce also with 4 for the glyphs Ka2-6--9, i.e. counting backwards from the end of the text on side b we should search for glyph number 9, and then glyph number 10 will be the searched for number 150:
 |
 |
 |
 |
 |
| *Kb5-20 |
*Kb5-19 |
*Kb5-18 |
*Kb5-17 |
*Kb5-16 |
| 1 |
2 |
3 |
4 |
5 |
 |
 |
 |
 |
... |
| *Kb5-15 |
*Kb5-14 |
*Kb5-13 |
*Kb5-12 |
| 6 |
7 |
8 |
9 |
10 |
Glyph number 150 is destroyed. We can check if the result is correct by going forward 75 glyphs beyond Kb1-11:
|
Ka1 |
*24 |
*29 |
|
Ka2-1 --
Ka2-5 |
5 |
|
Ka2-6 -- Ka2-22 |
17 |
82 |
|
Ka3 |
21 |
|
Ka4 |
16 |
|
Ka5 |
14 |
|
Kb1-1 --
Kb1-14 |
14 |
|
Kb1-15 -- *Kb1-22 |
*8 |
*48 |
|
Kb2 |
*18 |
|
Kb3 |
16 |
|
Kb4-1 --
Kb4-6 |
6 |
|
Kb4-7 -- Kb4-19 |
13 |
*33 |
|
Kb5 |
*20 |
|
sum |
*192 |
3 (Kb1-12--14) + 48 + 13 = 64 and then the 11th glyph in line Kb5 will be number 150 (counted from Ka2-10). Glyph number *Kb5-11 is destroyed (exactly as we arrived at going backwards).
The design of *Kb5-12 is similar to that in Kb4-7, hardly a coincidence:
| ordinal numbers counted from the 2nd Rei (Ka3-15) |
|
 |
 |
 |
| Kb4-6 |
Kb4-7 |
Kb4-8 |
Kb4-9 |
| 99 |
1 |
2 |
3 |
| ordinal numbers counted from the 1st Rei (Ka2-10) |
... |
|
|
|
| *Kb5-12 |
*Kb5-13 |
*Kb5-14 |
| 150 |
1 |
2 |
3 |
The distance from Kb4-7 to *Kb5-12 is 12 + 12 = 24 glyphs.
4 * 7 = 28 (measure for the moon) and 5 * 12 = 60 (measure for the sun).