TRANSLATIONS

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20

...

21

...

22

...

23

Kb2-107 Kb2-108

Kb2-111

Kb3-4

Kb3-8

*Kb2-12 *Kb2-13

*Kb2-16

*81 *85
*71 *72

*75

Earlier I must have made a mistake by assigning number *84 to Kb3-8.

Given the signs of bending around and of humpback, it is time to look again at the structure of the calendar in K.

K period no. number of glyphs
1, 2, 3 7 + 3 + 4 = 14 28 14
4, 5, 6 3 + 2 + 3 = 8 22
7, 8, 9 2 + 2 + 2 = 6 28
10, 11, 12 2 + 3 + 2 = 7 *28 35
13, 14, 15 3 + 2 + 3 = 8 43

16

*13 *56
17 3 *29 *59
18, 19, 20 *7 + 4 + 4 = *15 *74
21, 22, 23 3 + 6 + 2 = 11 *85
24, 25, 26 2 + 3 + 3 = 8 30 *93
27, 28, 29 5 + 4 + 5 = 14 *107
30, 31 4 + 4 = 8 *115
32, 0 3 + 7 = 10 10 *125

Possibly we should relocate period 20 to the following group, and if so, then a mirrored changed ought to be made by moving period 13 to the preceding group:

K period no. number of glyphs
1, 2, 3 7 + 3 + 4 = 14 28 14
4, 5, 6 3 + 2 + 3 = 8 22
7, 8, 9 2 + 2 + 2 = 6 28
10, 11, 12, 13 2 + 3 + 2 + 3 = 10 15 *28 35
14, 15 2 + 3 = 5 43

16

*13 *56
17 3 *29 *59
18, 19 *7 + 4 = *11 *26 *70
20, 21, 22, 23 4 + 3 + 6 + 2 = 15 *85
24, 25, 26 2 + 3 + 3 = 8 30 *93
27, 28, 29 5 + 4 + 5 = 14 *107
30, 31 4 + 4 = 8 *115
32, 0 3 + 7 = 10 10 *125

The resulting new numbers 15 and *26 are reasonable - possibly marking the final of moon respectively of sun. Also, the geometric progression in number of periods in the groups are beautíful: 4, 2, 1 mirrored as 1, 2, 4.

Another possibility is to group together periods 16-17 and reach *16 glyphs. The pattern then becomes:

28 + 15 + *16 + *26 + 30 + 10 = 43 + *42 + 40 = *125

Wouldn't it then be nicer with 41 instead of 40, reaching *126?

6 * 21 = 3 * 42 = 121

34

Ga7-18

Ga7-19

Ga7-20

32

Kb5-103

Kb5-104

Kb5-105

Kb5-106

*Kb5-4

*Kb5-5

*Kb5-6

*Kb5-7

The mago glyphs in period 6, are they signs which should make us reconsider the structures in G and K?

6

Ga3-22

Ga3-23

Ga3-24

6

Ka4-13

Ka4-14

Ka4-15

There are 3 'humpbacks' among the kai glyphs in K, blackmarked below because they carry no henua. A hump excludes a henua in front - henua glyphs indicate sunlight.

Ka3-3 Ka3-21 Ka4-3 Ka4-7 Ka4-10 Ka4-12
Ka4-15 Ka5-1 Ka5-3 Ka5-5 Ka5-7 Ka5-10
Ka5-12 Kb1-1 Kb1-3 Kb1-6 Kb1-104 Kb2-102
Kb2-106 Kb2-110 Kb2-111 Kb2-113 Kb3-4 Kb3-6
Kb3-8 Kb3-10 Kb3-13 Kb3-16 Kb4-5 Kb4-9
Kb4-14

The boat-like henua sign in Ka4-15 is reversed in Kb3-8 and I have redmarked them to focus our attention. Moreover, in Kb2-110 we can see the final of the season which appears to begin at Ka4-15.

6 20 23
Ka4-15 Kb2-110 Kb3-8

The final of the 23rd period is definitely connected with a reflection of the 6th period.

Counting periods long (inclusively), we get 1 + 16 + 1 = 18 periods, counting them short (exclusively) we get 16 periods. A short count could be used for the prominent part of a moon calendar, while counting long could be used for the prominent part of a sun calendar.

Counting glyphs long by including all glyphs in the 6th period we reach 3 + 6 + *28 + *29 = *66. Counting short (excluding all glyphs in the 6th period, and also all those in the 23rd period, we get *66 - 3 - 2 = *61. Neither result is convincing.

If we relocate period 0 to the beginning of the calendar (a step we should have taken much earlier), we reach 29 with Ka4-15, as if the period of darkness ends at the mago period (6):

K period no. number of glyphs
0 7 29 7 7
1, 2, 3 7 + 3 + 4 = 14 28 14
4, 5, 6 3 + 2 + 3 = 8 22
7, 8, 9 2 + 2 + 2 = 6 28
10, 11, 12, 13 2 + 3 + 2 + 3 = 10 15 *28 35
14, 15 2 + 3 = 5 43

16

*13 *56
17 3 *29 *59
18, 19 *7 + 4 = *11 *26 *70
20, 21, 22, 23 4 + 3 + 6 + 2 = 15 *85
24, 25, 26 2 + 3 + 3 = 8 30 *93
27, 28, 29 5 + 4 + 5 = 14 *107
30, 31 4 + 4 = 8 *115
32 4 4 *126

I at the same time have increased period 32 from 3 to 4 glyphs. But I have not changed the accumulated sums (14, 22, 28 etc) - with the exception of *126.

I have not changed the number of glyphs for period 0. It is still listed as 7 glyphs, although evidence points to it containing maybe only 2 glyphs:

0
Ka3-13 Ka3-14
Ga2-25 Ga2-26

These two glyphs maybe stand for the two halves of the year. Instead of *126 we would then have *121 (= 11 * 11). Or we could once again set period 32 as 3 glyphs, giving the more satisfactory *120. Let us try out this solutin:

K period no. number of glyphs
0 2 24 30 2
1, 2, 3 7 + 3 + 4 = 14 16
4, 5, 6 3 + 2 + 3 = 8 24
7, 8, 9 2 + 2 + 2 = 6 30
10, 11, 12, 13 2 + 3 + 2 + 3 = 10 15 *28 40
14, 15 2 + 3 = 5 45
16 *13 *16 *58
17 3 *29 *61
18, 19 *7 + 4 = *11 *26 *72
20, 21, 22, 23 4 + 3 + 6 + 2 = 15 *87
24, 25, 26 2 + 3 + 3 = 8 30 *95
27, 28, 29 5 + 4 + 5 = 14 *109
30, 31 4 + 4 = 8 *117
32 3 3 *120

The solution appears satisfactory. For instance: 365 - 360 = 5 = the number of glyphs in period 32 together with those in period 0:

32

0

*Kb5-4

*Kb5-5

*Kb5-6

Ka3-13 Ka3-14

Is this the way to bind the years together? 5 + 3 = 8 and 6 + 14 = 20.

Back to the basic questions: It seems probable that mago indicates how light arrives and the humpback how darkness arrives.

Is mago a symbol for Ana-mua, the entrance, and the humpback a symbol for Ana-muri, the exit?

Antares is the bright star close to the head (right) in the outline of Scorpio above.