|
6. In
order to reach a travelling time of 182 days (instead of the too
large number 2 * 96 = 192) the explorers had to rest for 10 days,
say 5 days at
Haga Takaúre and 5 at Haga Hônu.
Below I have, though, put a question mark for 5 days
at Haga Takaúre, because the explorers are said to have spent
7 days there (not 5). 7 days would disturb the picture, but could be
justified because summer would then be 89 + 91 = 180 days.
|
1st quarter |
2nd quarter |
3rd quarter |
4th quarter |
|
He Anakena
(July) |
Tagaroa uri
(October) |
Tua haro
(January) |
Vaitu nui
(April) |
|
Te Pei |
Te Pou |
Tama |
One Tea |
Mahatua |
Taharoa |
Nga Kope Ririva |
Te Pu Mahore |
|
Hora iti
(August) |
Ko Ruti
(November) |
Tehetu'upú
(February) |
Vaitu potu
(May) |
|
Hua Reva |
Akahanga |
Hanga Takaure |
Poike |
Hanga Hoonu |
Rangi Meamea |
Te Poko Uri |
Te Manavai |
|
Hora nui
(September) |
Ko Koró
(December) |
Tarahao
(March) |
He Maro
(June) |
|
Hatinga Te Kohe |
Roto Iri Are |
Pua Katiki |
Maunga Teatea |
Peke Tau O Hiti |
Mauga Hau Epa |
Te Kioe Uri |
Te Piringa Aniva |
|
84 |
96 - 5 (?) = 91 |
96 - 5 = 91 |
84 |
Another manipulation surely must be made in order to expand the 2 *
84 = 168 days of winter to 182. An addition is necessary.
We can consult the time schedule of the explorers to see what
happened at the 3rd and last of the haga stations mentioned
in the table above, viz. Akahanga. Once the royal child
Tuu Maheke had buried his father, king Hotu A Matua,
there, in Hare O Ava. It is quite appropriate for a sun king
to end at the 10th station. Also, aka means 'anchor' -
Akahanga, a bay in which to drop anchor.
"They went on and reached Akahanga, took a
look at it and looked around. They said: 'This is it!' and gave the
name 'Akahanga A Hau Maka.' They went on ..."
The explorers did not spend much time at Akahanga. In
cyclical time you know what will happen, you know the future, and
the explorers well understood that at Akahanga the king -
which had not yet arrived to the island - would 'drop anchor'. |
Then follows:
|
7. Later
on, at Haga Hônu, they made camp and caught 'great numbers (?
ka-mea-ro) of fish (3 kinds). But they had no fire to prepare
the fish on. One of them had to go back to Haga Te Pau to fetch
it. This is the information we need. Haga Te Pau is located
in the middle of He Maro, not mentioned in the kuhane
journey but obviously very important. The explorers had landed there
(another bay for anchorage) on He Maro 1.
On He Maro 10 they had left Haga Te Pau and gone up to
construct a house and to plant yams. Mako'i went to survey
the crater on He Maro 15. So far we can count to 10 days of rest
at Haga Te Pau.
On the 5th day of Anakena they returned to Haga Te Pau, after
having completed the house and the yam plantation. Later they left
for Te Pou and slept there on the 10th day of Anakena.
It seems as if we can add 5 days, and the total number of rest days at Haga Te
Pau will then be 15:
|
1st quarter |
2nd quarter |
3rd quarter |
4th quarter |
|
He Anakena
(July) |
Tagaroa uri
(October) |
Tua haro
(January) |
Vaitu nui
(April) |
|
Te Pei |
Te Pou |
Tama |
One Tea |
Mahatua |
Taharoa |
Nga Kope Ririva |
Te Pu Mahore |
|
Hora iti
(August) |
Ko Ruti
(November) |
Tehetu'upú
(February) |
Vaitu potu
(May) |
|
Hua Reva |
Akahanga |
Hanga Takaure |
Poike |
Hanga Hoonu |
Rangi Meamea |
Te Poko Uri |
Te Manavai |
|
Hora nui
(September) |
Ko Koró
(December) |
Tarahao
(March) |
He Maro
(June) |
|
Hatinga Te Kohe |
Roto Iri Are |
Pua Katiki |
Maunga Teatea |
Peke Tau O Hiti |
Mauga Hau Epa |
Te Kioe Uri |
Te Piringa Aniva |
|
84 |
96 - 7 = 89 |
96 - 5 = 91 |
84 + 15 = 99 (?) |
|
363 (?) |
With 7 days' rest at Haga Takaúre summer would
be 180 days long and the calendar year would be 180 + 84 + 99 = 363
days. And additional 2 days ought to be located in the winter
quarters it seems. |
I decided to recount the
Pachamama skirt. I do not remember how I did it last time, but this time
I decided to count the signs by columns, a method which proved effective and
illuminating:
|
left leg from us seen |
|
columns 1-5 |
columns 6-8 |
columns 9-12 |
columns 13-15 |
|
5 * 5 = 25 |
3 * 6 = 18 |
4 * 7 = 28 |
23 |
|
94 |
|
right leg from us seen |
|
columns 11-15 |
columns 8-10 |
columns 5-7 |
columns 1-4 |
|
5 * 5 = 25 |
16 |
3 * 6 = 18 |
4 * 6 = 24 |
|
83 |
I have ordered the columns in the
right leg as if seen in a mirror in order to see how right compares to left. 94
+ 83 = 177 = 354 / 2. My earlier result is confirmed.
The redmarked numbers in the left leg
are reflected in the right leg, though with 16 (the growing moon number an
Easter Islander would say) inserted. 4 * 7 = 28 is also recognizable for an
Easter Islander. 16 in the right leg must correspond to 28 in the left leg, and
both are moon numbers.
16 and 23 are not easily discerned as
multiples of two numbers. 16 is incised in three columns with the pattern 6, 5,
6, while 23 is more complex:
|
column 13 |
column 14 |
column 15 |
|
1 |
6 |
6 |
|
5 |
5 |
|
11 |
6 |
6 |
|
23 |
If it wasn't for the split 13th
coloumn in the left leg, the number of columns would be 15 + 15 = 30.
Presumably the
intention was to count to 29 true columns, and then to consider the split 13th
column as indicating 'half the time a column, half not', thereby arriving at
29.5 columns (= nights in month). Maybe Ca7-21 is the corresponding 'half the
time a night' in the Mamari moon calendar?
 |
 |
 |
 |
|
Ca7-21 |
Ca7-22 |
Ca7-23 |
Ca7-24 |
|
column 13 |
column 14 |
column 15 |
midpoint |
| te kava - erua
marama |
e marama noho i tona nohoga |
te hare pure e tagata noho ki
roto |
Ca7-23 and Ca7-24 seem
to reflect the same idea as 23 and 24 around the midpoint in the Pachamama
skirt. Ca7-24 would correspond to 'column 16' (te pito of the skirt).
Given a location south
of the equator and south at her back, Pachamama will 'see' the rising sun
at right, i.e. for us - watching her 'face' - it means we are looking towards
south and have rising sun at left. We therefore ought to 'read' the skirt from
left to right. However, number 16 appears in the right leg (seen from us). Moon
is rising in the west and growing moon is probably, therefore, illustrated in
the right leg (seen from us).
The 'face' of
Pachamama is to be read as the 'face' of the moon, not of the sun. The
'double-circle' signs should refer to the moon, not to the sun. 28 in the left
leg (seen from us) is a statement that this leg is the 2nd of the two moon legs.
The creator of the
Mamari moon calendar has the opposite perspective, it seems. Time runs
towards the right, the sun perspective, even in a moon calendar. But then, we
must conclude, Ca7-21 is located in the 1st of the two 'moon legs', not in the
2nd as in the skirt of Pachamama.
Metoro has identified
Ca7-21--22 as related to kava, probably having noted the two oppositely
oriented signs connected by a 'kava-limb'. 5 + 5 (a double 'fire')
possibly generates a new 1, at least half of the times.
The middle part of the skirt is a
separate unit, encompassing 23 + 24 = 47 signs:
|
left |
middle |
right |
sum |
|
71 |
47 |
59 |
177 |
|
118 = 2 * 59 |
59 - 47 = 12. We probably ought to
reshuffle columns 9-12 into 3 * 4 = 12 (bottom rectangle) plus 4 * 4 = 16 (top
square):
|
left leg from us seen |
|
columns 1-5 |
columns 6-8 |
columns 9-12 |
columns 13-15 |
|
5 * 5 = 25 |
3 * 6 = 18 |
16
+ 12 = 28 |
23 |
|
94 |
|
right leg from us seen |
|
columns 11-15 |
columns 8-10 |
columns 5-7 |
columns 1-4 |
|
5 * 5 = 25 |
16 |
3 * 6 = 18 |
4 * 6 = 24 |
|
83 |
An invisible break occurs in
columns 9-12 (it seems) to enable a triplet of 59:s.
59 = 25 + 18 + 16 according to
both legs, i.e. 50 + 36 + 32 can be imagined. 10 fives for the sun, 36 tens
for the year and 32 as the 6th term in the growth series: 1, 2, 4, 8, 16, 32
...
The invisible break can be translated into a break in the month:
(59 + 59) / 177 = ⅔ and applied to a
30-day month it means a break will occur with the 20th day.