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3. We should not complicate matters - my first counting attempt is presumably the best way to do it:

Ga3-5 Ga3-9 Ga3-16 Ga3-19 Ga3-21 Ga3-24
6 5 (11) 5 (16) 5 (21) 5 (26) 5 (31)
Ga4-4 Ga4-6 Ga4-8 Ga4-10 Ga4-13
5 (36) 5 (41) 5 (46) 6 (52) 6 (58)
Ga4-15 Ga4-19 Ga4-22 Ga4-27 Ga5-3
6 6 (12) 6 (18) 4 (22) 6 (28)
Ga5-9 Ga5-16 Ga5-21 Ga5-29 Ga6-4
5 5 (10) 5 (15) 5 (20) 4 (24)
Ga6-8 Ga6-11 Ga6-16 Ga6-18 Ga6-20
5 (29) 5 (34) 4 (38) 4 (42) 5 (47)
Ga6-23 Ga6-26 Ga6-29 Ga7-4 Ga7-10
5 (52) 4 (56) 5 (61) 4 (65) 5 (70)

If we should try to improve on the table one possibility could be to subtract the bad (4-feather) numbers:

all feathers no 'black' ones only 'red' ones
58 58 40
28 24 0
70 50 50
156 132 90

There are no 'black' (strings with 4 feathers) in the first group and there are no 6-feather strings in the last group.