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2. These are the relevant glyphs:

Ga3-5 Ga3-9 Ga3-16 Ga3-19 Ga3-21 Ga3-24
Ga4-4 Ga4-6 Ga4-8 Ga4-10 Ga4-13
Ga4-15 Ga4-19 Ga4-22 Ga4-27 Ga5-3
Ga5-9 Ga5-16 Ga5-21 Ga5-29 Ga6-4
Ga6-8 Ga6-11 Ga6-16 Ga6-18 Ga6-20
Ga6-23 Ga6-26 Ga6-29 Ga7-4 Ga7-10

I have divided the glyphs in 3 groups by using Ga4-13 and Ga5-3, which have their henua signs open at top, guessing their locations might in some way correspond to those where the L bead string in the southern bowl of Libra (in Flamsteed's picture) is disappearing below first the C and then the R string.

The number of feather marks:

6 5 5 5 5 5 5 5 5 6 6
6 11 16 21 26 31 36 41 46 52 58
6 6 6 4 6
6 12 18 22 28
64 70 76 80 86
5 5 5 5 4 5 5 4
5 10 15 20 24 29 34 38
91 96 101 106 110 115 120 124
4 5 5 4 5 4 5
42 47 52 56 61 65 70
128 133 138 142 147 151 156

The total is 156 (= 12 * 13). 58 + 28 + 70 = 156.

156 = 6 * 4 + 18 * 5 + 7 * 6 = 24 + 90 + 42. These numbers suggest the number of feathers could refer to number of days (90), number of hours (24), respectively number of weeks (6 weeks = 42).

The number of feathers above evidently can be interpreted as double-feathers, in which case the total number of feathers perhaps should be 2 * 156 = 312 (2 less than 314).

The new total would then be 312 (= 24 * 13). 106 + 56 + 140 = 312.

312 = 6 * 8 + 18 * 10 + 7 * 12 = 48 + 180 + 84. These numbers suggest the number of feathers could refer to number of days (180), number of hours (48), respectively number of weeks (12 weeks = 84).

But I think we possibly should disregard those double-feathers which are in Ga4-13 and Ga5-3:

6 5 5 5 5 5 5 5 5 6 -
6 11 16 21 26 31 36 41 46 52 -
6 6 6 4 -
6 12 18 22 -
58 64 70 74 -
5 5 5 5 4 5 5 4
5 10 15 20 24 29 34 38
79 84 89 94 98 103 108 112
4 5 5 4 5 4 5
42 47 52 56 61 65 70
116 121 126 130 135 139 144

52 + 22 + 70 = 144 (= 12 * 12).

144 = 6 * 4 + 18 * 5 + 5 * 6 = 24 + 90 + 30.

Or perhaps 288 = 104 + 44 + 140 = 6 * 8 + 18 * 10 + 5 * 12 = 48 + 180 + 60.