There are 30 glyphs in line Cb9. The manzil Simak is ruled by Spica, but Syrma has no ruling star (like the previous Azzubra and Assarfa).
The number of glyphs on side a of the P tablet is 599, and 599 - 365 + 80 = 314 = 177 + 137. Kava glyphs follow:
The double nuku in Cb9-28 has no 'eyes' (mata). The manzil Az Zubana was ruled by Acubens and Pollux ruled Al Muakhar:
Why is there a mago in Cb9-18? Antares rose heliacally in November 25 (day 329 in an ordinary year). 329 - 80 = 249, the heliacal day. The manzil date at November 25 is 193. Antares was important as the announcer of a change from winter to summer. 91 * 8 = 728 = 2 * 364, which could be a Sign of where a '2nd year' was due to begin. Counting from Spica there ought to be 249.1 - 202.7 = ca 46 glyphs to Antares and in an ordinary year Spica was rising heliacally in October 10 (day 283):
The distance from mago in Cb2-10 to mago in Cb9-18 is 184 days:
The distance from Antares to Aldebaran is also 184 days. Could it be Aldebaran in Cb9-18? 80 + 68.2 (RA day for Aldebaran) = 148 (May 28 in an ordinary year). 148 + 181 = 329. The distance from Aldebaran to Antares agrees with the key nakshatra number 181 and the answer to my question must be yes:
For Antares: 80 + 249.1 = 329 (November 25 in an ordinary year). 329 + 181 = 510. 510 - 365 = 145 (May 25, 5-25, in an ordinary year). We can then understand Ga1-1, it is the nakshatra position of Antares:
I intend to use blue for heliacal star positions and black for their nakshatra positions (181 days later). Mago in Cb2-10 is 184 days earlier than nakshatra Aldebaran in November 20. 68.2 - 184 + 365¼ = ca 249.45, and it has to be Antares:
The Antares mago is leaner and opens its mouth more than the Aldebaran mago, perhaps because south of the equator winter precedes the heliacal rising of Antares. How about Spica? Once again, 80 + 202.7 = 283 (October 10 in an ordinary year). 283 + 181 = 464. 464 - 365¼ = 99 (April 9 in an ordinary year). May 25 (nakshatra Antares) - April 9 (nakshatra Spica) = 145 - 99 = 46. In a leap year day 464 is April 8, in an ordinary year it is April 9:
365 - 181 = 184 = the distance from a nakshatra star to its RA day. Nakshatra Spica ought to at the 'fake Rogo' in Ca14-22 because it is the central glyph in the triplet. The great vero with a great dot in front is the position of Spica's heliacal rising - i.e. both Ca14-22 and Cb8-6 represent Spica dates in an ordinary year. I have put the broad hanau in Cb8-7 (the first day after the heliacal rising of Spica) at left instead of at right in my table above in order to visualize the distance from the heliacal rising to the nakshatra position. The time cycle of Spica in a solar year covers 181 + 184 = 365 days. The 'egg' comes before the 'hen' (Ca14-22). But 142 * 2 = 284 points at October 10 in a leap year. | ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
