Once again, in this maze of conflicting
ideas we have to choose a simple alternative and I
think this it to rely on Q, because its fractured text
needs stability from number. Probably the text covers a solar year
of the Gregorian type, given that 2 glyphs are counted per day.
|
a1 |
*23? |
23 |
b1 |
51 |
51 |
|
a2 |
43 |
66 |
b2 |
46 |
97 |
|
a3 |
41 |
107 |
b3 |
*51? |
148 |
|
a4 |
*43? |
150 |
b4 |
*39? |
187 |
|
a5 |
55 |
205 |
b5 |
*42? |
229 |
|
a6 |
*49? |
254 |
b6 |
*33? |
262 |
|
a7 |
*41? |
295 |
b7 |
*39? |
301 |
|
a8 |
47 |
342 |
b8 |
32 |
333 |
|
a9 |
45 |
387 |
b9 |
*12? |
349 |
|
sum |
*387? |
sum |
*345? |
This basic counting rule could have
been used to inform the reader of the possibility to
look at the whole text as a description of the solar
year, with each day corresponding to one glyph for
daytime and one glyph for nighttime.
Against such a background for the total
Q structure there could then be additional alternative readings,
e.g. to count each glyph as a night according to
some other calendar. 295 at the end of line Qa7
could identify a shorter cycle reflecting the
subpattern of a longer sequence of nights with a
cycle needing a renewal around
13 * 31 = 403 nights:
 |
 |
 |
 |
 |
|
Ha8-6 |
Ha8-7 |
Ha8-8 (403) |
Ha8-9 |
Ha8-10 |
 |
 |
 |
 |
- |
|
*Qa7-38 |
*Qa7-39 |
*Qa7-40 |
*Qa7-41 (295) |
 |
 |
 |
 |
 |
|
Pa7-24 |
Pa7-25 |
Pa7-26 |
Pa7-27 |
Pa7-28 (403) |
403 = 295 + 108 (= 4 * 27 = 2 * 54 =
2 / 7 * 378 = 540 / 5).
In the above we recognize the
pattern in Ca3-6--7, which probably refers to the
beginning of the manzil year:
|
Alrescha 15 (365) |
|
Sheratan 1 |
2 |
3 |
|
May 16 (136) |
17 |
18 |
19 |
 |
 |
 |
 |
|
Ca3-5 |
Ca3-6 (57) |
Ca3-7 |
Ca3-8 |
|
ihe tapamea |
e tagata mau toki ki
te henua |
e hokohuki mau ki te
matagi |
kiore i te henua |
|
Maia, Asterope, Merope (55.6), Alcyone
(56.1), Pleione,
Atlas (56.3) |
no star listed |
Menkhib (57.6) |
Zaurak (58.9), λ Tauri (59.3) |
Although the rule to count each glyph as a
night (po, day) may have been a basic common rule
for all the rongorongo texts, in Q the main goal evidently
could have been to describe the shorter cycle of the solar year:
|
*Qa7-18 |
*272 |
May
16 (136) |
| |
*338 |
338
/ 2 = 169 = 305 - 136 |
|
*Qb5-36 |
*610 |
November 1 (305) |
| |
*126 |
126
/ 2 = 63 = 368 - 305 |
|
End
of text |
*736 |
January 3 (368) |
May 16 corresponds to the last day in
the manzil calendar and therefore the Q text could have
begun
with January 1.
January 3 is the day after Qalb al
Akraab 9:
|
Qalb al Akraab 5 |
6 |
7 (229) |
|
December 29 |
30 (364) |
31 |
 |
 |
 |
|
Ca10-28 |
Ca10-29 (284) |
Ca11-1 |
|
te inoino |
te tagata |
E inoino |
|
ζ Pavonis (283.4) |
λ Cor. Austr. (283.6), Double Double
(283.7), ζ Lyrae (283.8), φ Sagittarii
(284.0) |
μ Cor. Austr. (284.6),
η Cor. Austr., θ Pavonis (284.8), Sheliak, ν
Lyrae (285.1) |
|
June 30 |
July 1 (182) |
2 |
|
Al Tuwaibe' 5 |
6 (46) |
7 |
|
Mebsuta
(100.7), Sirius
(101.2), ψ5 Aurigae (101.4) |
ν Gemini (101.6,
ψ6 Aurigae (101.7), τ Puppis (102.2), ψ7
Aurigae (102.4) |
ψ8 Aurigae
(103.2) |
|
Qalb al Akraab 8 |
9 (231) |
|
January 1 |
2 |
 |
 |
|
Ca11-2 (286) |
Ca11-3 |
|
te inoino |
kua haga |
|
λ Pavonis (285.7),
Ain al Rami (286.2),
δ Lyrae (286.3) |
κ Pavonis (286.5), Alya (286.6), ξ
Sagittarii (287.1), ω Pavonis (287.3), ε
Cor. Austr., Sulaphat (287.4)
|
|
July 3 |
4 (185) |
|
Al Tuwaibe' 8 |
9 (49) |
|
Alhena
(103.8), ψ9 Aurigae (103.9) |
Adara
(104.8), ω Gemini (105.4) |
|
Shaula 1 |
2 |
3 |
4 (600) |
5 (236) |
6 |
|
January 3 |
4 |
5 |
6 (736) |
7 (372) |
8 |
 |
 |
 |
 |
 |
 |
|
Ca11-4 |
Ca11-5 |
Ca11-6 (290) |
Ca11-7 |
Ca11-8 |
Ca11-9 |
|
tupu te raau i te vai |
te moko |
te marama |
te kava |
manu rere |
te mauga hiku hia |
|
λ Lyrae (287.7), Ascella (287.9),
Nunki
(288.4), ζ Cor. Austr. (288.5) |
19h (289.2) |
δ Cor. Austr. (289.8),
Al Baldah,
Alphekka Meridiana (290.1), β Cor.
Austr. (290.2) |
Aladfar (291.1), Nodus II (291.5) |
ψ Sagittarii (291.6), θ Lyrae
(291.8) |
Arkab Prior (293.0), Arkab
Posterior,
Alrami
(293.2) |
|
Manubrium
(288.8), γ Cor. Austr. (289.3), τ
Sagittarii (289.4), ι Lyrae (289.5) |
|
July 5 |
6 |
7 (188) |
8 |
9 |
10 |
|
Al Tuwaibe' 10 |
11 |
12 |
13 |
Heka 1 (54) |
2 |
|
Alzirr (105.7), Muliphein (105.8) |
7h (106.5) |
no
stars listed |
Wasat (109.8) |
Aludra (111.1) |
|
Wezen (107.1) |
But day 736 counted
from January 1 in the previous year
corresponds to January 6 and the
total number of glyphs on the Q tablet
(*736) could therefore point at January 6
rather than at January 3:
|
*Qa7-18 |
*272 |
May
18 (136) |
| |
*338 |
338
/ 2 = 169 = 305 - 136 |
|
*Qb5-36 |
*610 |
November 3 (305) |
| |
*126 |
126
/ 2 = 63 = 368 - 305 |
|
End
of text |
*736 |
January 6 (368) |
I have here assumed the
counting should begin at January 3 instead
of with January 1. This means day
136 in the Gregorian calendar (May 16) will
correspond to day 134 in my assumed 368-day
long Q-cycle.
November 3 (307) is 61 days
before the end of this 368 day long year. And
also the C text has a break in time here,
where the sitting persons look back
respectively ahead in Janus fashion:
|
12 |
Auva 13 |
Simak 1 |
2 |
3 |
4
(174) |
|
November 1 |
2 |
3 |
4 |
5 |
6 (310) |
 |
 |
 |
 |
 |
 |
|
Ca8-26 (225) |
Ca8-27 |
Ca8-28 |
Ca8-29 |
Ca9-1 |
Ca9-2 (230) |
|
- |
- |
- |
- |
Ohiro |
Oata |
|
te ahi ki
te rima aueue - te ika |
tupu te ure o
te henua |
erua kiore |
Te marama erua |
|
Kochab (225.0) |
Ke Kwan (226.3), Ke Kwan (226.4) |
Zuben Elakribi (226.8), Nekkar
(227.3) |
15h (228.3) |
λ Lupi (228.9) |
κ Lupi (229.7), ζ Lupi (229.8) |
|
π Lupi (227.9),
Zuben Hakrabim (228.3) |
|
3 |
May 4 |
5 (125) |
6 |
7 |
8 |
|
2 |
Alrescha 3 |
4
(354) |
5 |
6 |
7 |
|
no star listed |
Acamar (43.6) |
Menkar (44.7) |
3h (45.7) |
no star listed |
Botein (46.9) |
|
Algol (45.9), Misam (46.2) |
The basic time structure
evidently is the same in C as in Q.
Possibly the night when
Atlas - at the end of the Pleiades
cluster - culminated (December 31 in
rongorongo times) was used to determine
the number structure 136 + 229 = 365:
|
|
365
days |
|
|
(80
+ RA
/
24h
*
365¼) |
|
Day
of
culmination |
|
|
Atlas |
May
16
(136) |
228 |
December
31
(365) |
135 |
|
|
229 |
136 |
But then, instead of choosing the
Gregorian date May 16 as the beginning
of summer it was decided the beginning
should be 2 days later. Perhaps 5-16 (51 * 6 = 306)
gave a wrong number sign and the date
May 18 was preferable.
51 * 8 = 408 = 368 + 40.
36 * 8 = 2 * 144 = 288
and 80 + 288 = 368.
|