*Celaeno*	16 Tauri	5.45	24º 08' N	03h 42m	56.3	464.3	463½
*Asterope*	21 Tauri	5.76	24º 24' N	03h 43m	56.6	464.6	463¾
*Alcyone*	η Tauri	2.85	23º 57' N	03h 45m	57.1	465.1	464¼
*Atlas*	27 Tauri	3.62	23º 54' N	03h 46m	57.3	465.3	464½
*Pleione*	28 Tauri	5.05	23º 59' N	03h 46m	57.3	465.3	464½


Gb8-25	Gb8-26 (468)	Gb8-27	Gb8-28	Gb8-29	*Gb8-30 (64)**

The cycle, as defined by 22 (~ 7 * π), is completed with day number 56 (= 7 * 8), and this is were the 'lost Pleiad' Celaeno ought to be - at the beginning of the star cluster - whereas Atlas is at the end of it:

It must be mentioned that there is one more 'egg-headed' manu rere in the text, viz. Gb1-12 (were we can read 11 * 2 = 22):


Gb1-4	Gb1-5	*Gb1-6 (300)**


Gb1-7	Gb1-8	Gb1-9	Gb1-10	Gb1-11	Gb1-12 (242)


Gb1-13	Gb1-14	Gb1-15	Gb1-16	Gb1-17	Gb1-18	Gb1-19	*Gb1-20 (314)**


Gb1-21	Gb1-22	Gb1-23	Gb1-24	Gb1-25	*Gb1-26 (320)**	Gb2-1

The corresponding right ascension can be counted as (242 + 64) / 365¼ * 24h = 20h 6m or as 20h 24m by using a cycle with 360 days. Somewhere in this interval there should be a prominent star:

*Gredi*	α Capricorni	20h 15m
Dabih	β Capricorni	20h 18m
Sadir	γ Cygni	20h 20m
*Peacock*	α Pavonis	20h 21m

A Peacock is a bird and α Pavonis is a possible choice, but perhaps Sadir is better: "... Sadr ... from Al Sadr al Dajājah, the Hen's Breast ..." (Allen)

Counting from Celaeno (03h 42m = 222m) to Sadir (20h 20m = 1220m) there are 998 minutes. Maybe γ Cygni is where the 'lost Pleiad' has landed:

But the numbers point at Peacock, because it is around 999m beyond Celaeno. In Bode's picture he has drawn 10 'eyes' in the peacock's tail and the 11th eye (moving in time from right to left) is α Pavonis: