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226. The date in the year 3149 BC, when the false sun bird Itzam-Yeh (alias Seven-Macaw) had been defeated, was 28 May and at the time of rongorongo the alpha-star of the Bull (Aldebaran) rose heliacally in May 28 (148):

Egyptian head Phoenician aleph Greek alpha Α (α)

In Gardiner's sign list this is E2, aggressive bull.

no glyph
Ga1-1 Ga1-2
HYADUM II = δ¹ Tauri (64.2) Net-19 (Crow)

AIN (Eye) = ε Tauri, θ¹ Tauri, θ² Tauri (65.7)

no star listed (66)
May 24 25 (145) 26
°May 20 (140) 21 (*61) 22
'April 27 28 (118) 29 (*39)
"April 13 14 (104) 15 (*25)
0h MARCH 22 (*1) 23 (82)
60 = 80 - 20 = 144 - 84 61 62

... There was no water in the village. The lakes and rivers were dry. Raven and Crow, two young girls who were having their first menstrual courses, were told to go and draw water from the ocean. Finding the journey too long, Raven decided just to urinate into her basket-bucket. She decieved no one and was severly scolded. Crow returned much later but with drinking water. As a punishment, Raven was condemned never to find water in the summer; only in winter would she find something to drink. For that reason the Raven never drinks during the hot months; she speaks with a raucous voice because of her dry throat ...

Ga1-3 Ga1-4 Ga1-5 Ga1-6
no star listed (67) Rohini-4 / Pidnu-sha-Shame-4 (Furrow of Heaven) / ANA-MURI-2 (Rear pillar - at the foot of which was the place for tattooing)

ALDEBARAN (The Follower) = α Tauri (68.2), THEEMIN = υ² Eridani (68.5)

no star listed (69) no star listed (70)
May 27 28 (148) 29 30
°May 23 (*63) 24 (144) 25 26
'April 30 (*40) 'May 1 (121) 2 3
"April 16 (*26) 17 (107) 18 19
MARCH 24 EQUINOX 26 (85) 27
63 148 - 84 65 66

Counting the number of precessional days from the year 3149 BC to my assumed base line year for the rongorongo texts we will find Aldebaran at that time would  have risen heliacally approximately (3149 + 1842) / 71 = 4991 / 71 = 70 right ascension days earlier than in May 28 (148), viz. around day 148 - 70 = 78 (19 March).

This was neither at the Julian equinox (25 March), nor at the Gregorian equinox (21 March), nor at the astronomically average equinox (20 March). But from day 78 (19 March) to the beginning of a half-year in 1 July (182) the distance was 104 days. 78 = 3 * 26 and 182 = 7 * 26, which means that in 3149 BC there had been 4 * 26 = 104 days from heliacal Aldebaran to 1 July.

... The Celtic year was divided into two halves with the second half beginning in July, apparently after a seven-day wake, or funeral feast, in the oak-king's honour ...

Counting the tresses of Pachamama (the World Mother) from right to left:

1

26

78

1

29

90

2

26

2

30

3

26

3

31

4

25

104

4

34

124

5

26

5

31

6

27

6

30

7

26

7

29

Total = 396 = 182 + 214

Thus the time frame at the Fall of the False Sun was 6 right ascension days earlier than those *64 corresponding to the position of Hyadum II at the time of rongorongo:

no glyph
Ga1-1 Ga1-2
HYADUM II = δ¹ Tauri (64.2) Net-19 (Crow)

AIN (Eye) = ε Tauri, θ¹ Tauri, θ² Tauri (65.7)

no star listed (66)
May 24 25 (145 = 290 / 2) 26
°May 20 (140) 21 (*61) 22
'April 27 28 (118 = 4 * 29½) 29 (*39)
"April 13 14 (104 = 3 * 26) 15 (*25)
0h MARCH 22 (*1) 23 (82)
60 = 80 - 20 = 144 - 84 61 62
15 March (74 = 144 - 70) 16 (75 = 300 / 4) 17
Ga1-3 Ga1-4 Ga1-5 Ga1-6
no star listed (67) Rohini-4 / Pidnu-sha-Shame-4 (Furrow of Heaven) / ANA-MURI-2 (Rear pillar - at the foot of which was the place for tattooing)

ALDEBARAN (The Follower) = α Tauri (68.2), THEEMIN = υ² Eridani (68.5)

no star listed (69) no star listed (70)
May 27 28 (148 = 78 + 70) 29 30
°May 23 (*63) 24 (144 = 78 + 66) 25 26
'April 30 (*40) 'May 1 (121 = 78 + 43) 2 3
"April 16 (*26) 17 (107 = 78 + 29) 18 19
MARCH 24 EQUINOX 26 (85) 27
63 148 - 84 65 86 - 20
18 March 19 (78 = 3 * 26) 3-20 21 (80 = 86 - 6)

6 * 71 = 426 and 3149 BC - 426 = 2723 BC when, according to a simple extrapolation without regard for the proper motions of the stars, Aldebaran (The Follower of the Pleiades) would have risen heliacally together with the Sun at the Julian equinox in MARCH 25 (84 = 7 * 12 = 6 * 14).