TRANSLATIONS

TRANSLATIONS

But maybe the creator of P regarded Sunday as not part of the week in the night - how could Sun belong there?

In C, we have seen, Sun is present just before the planets arrive. They arrive when sun leaves.

The other link, 'day numbers', leads to the following pages, the first two of which are:

Immediately beyond Saturn a sequence of glyphs follows, where we in Ca3-25 recognize the glyph type (cfr Gb6-26) which indicates winter solstice:


Ca3-14	Ca3-15	Ca3-16

Ca3-17	Ca3-18	Ca3-19	Ca3-20

Ca3-21 (72)	Ca3-22	Ca3-23	Ca3-24	Ca3-25

Instead of naming this type of 'person' honu vae kore ('without legs'), I have decided to label him Rogo (or Lono as he was called on Hawaii where he once was the main 'person' at winter solstice).

Thank you Metoro for this idea. He said tagata rogo at Ca3-25.

If also in C the Rogo glyph type indicates winter solstice we could use Ca3-25 as a point of reference in order to search for other cardinal points. But first we have to ascertain that there is no other similar glyph in C which could serve better for winter solstice.

These 12 glyphs are possible candidates and I have redmarked the most obvious ones:


Ca1-8	Ca3-25	Ca10-29	Ca11-3	Ca11-13
		7 on side a and 5 on side b
Ca14-219	Ca14-222	7 on side a and 5 on side b

Cb5-16	Cb5-18	Cb7-24	Cb7-26	Cb14-12

While Ca3-25 is single, these glyphs mostly come in pairs, for instance:


Cb5-16	Cb5-18		Cb7-24	Cb7-26

I interpret this evidence so that the single Ca3-25 should be at winter solstice. Pairs of glyphs close together usually refer to a late stage in a cycle.

5 * 18 = 90 and 7 * 26 = 182:

		55
Cb5-16	Cb5-18		Cb7-24	Cb7-26
110	112		168	170
502	504		560	562
*59 = 2 29.5**

110 etc are the ordinal numbers counted from Cb1-1 and 502 etc counted from Ca1-1.

59 = 2 * 29.5 is a fact independent of from where we count the ordinal numbers.

But 59 can either mean 2 lunar months or a single lunar month (because there might be needed 2 glyphs per day).

Maybe we should count 3 glyphs per day:


Cb5-16	Cb5-17	Cb5-18 (504)
504 / 3 = 168

168 + 64 = 232. But 168 may be the most relevant alternative. 168 = 7 * 24, cfr Cb7-24, where the ordinal number counted from Cb1-1 is 168:


Cb7-23	Cb7-24 (168)	Cb7-25 (561)
561 / 3 = 187 = 168 + 19
tagata ka pau	tagata rima oho ki te kihikihi - ki te ragi


Cb7-26 (562)	Cb7-27	Cb8-1	Cb8-2
koia ra kua mau - i te ahi	*e tagata rogo*	Hetu erua

Vero with a reversed growth (maro) at left says the sun light has gone away. Metoro agrees and says 'ka pau' (maybe ká pau?):

Ka, ká

Ka. Particle of the affirmative imperative, of cardinal numerals, of independent ordinal numerals, and of emphatic exclamation, e.g. ka-maitaki! how nice! Vanaga.

Ká. 1. To light a fire in order to cook in the earth oven (see umu): he-ká i te umu, he-ká i te kai. 2. Figuratively: to fire up the soul. To put oneself in a fury (with manava): ku-ká-á toona manava he has become furious. Vanaga.

1. Of T. 2. Imperative sign; ka oho, ka tere, ka ea, begone!; ka ko iha, a greeting T; ka mou, hush; ka oho, goodbye. 3. Infinitive sign; mea meitaki ka rava, a thing good to take; ka harai kia mea, to accompany. 4. A prefix which forms ordinals from cardinals. 5. The dawning of the day. 6. Different (? ke). Churchill.

The central Rogo glyph has nothing more to offer, there is only an empty hand in front. 561 = 300 + 261.

At Cb7-27 we once again encounter a tagata rogo, this one with the same hand gesture as the 3 glyphs preceding Rogo glyph. While reading C Metoro mentioned rogo only at Cb7-27 and Ca3-25:

75 316 170 177

Ca3-25 (76) Cb7-27 (563)

tagata rogo e tagata rogo

177 = 4 * 29.5 jumps into our eyes. When tagata rogo is emptyhanded 4 lunar months remain on side b (given 1 day per glyph).

There are only 348 glyphs on side b, clearly a part of the grand design the creator of C had in mind. There is no evident difference in area to write on compared with side a.

348 - 177 = 171 = 9 * 19.

177 + 75 = 252 = 7 * 36 = 14 * 18. Maybe the intention was to have 18 fortnights of absent Rogo before new year arrives.

76 = 4 * 19, and therefore 76 + 171 = 247 = 13 * 19.

From Ca3-25 up to and including Cb7-27 there are 317 + 171 = 488 glyphs, maybe 244 days

Rogo in Ca3-25 stands in the early part of side a, while Cb7-27 is close to the center of side b.

392 = 400 - 8. If side a is the 'front side', then the last 8 glyphs on side b could represent the 8 nights between the 'evening' and 'morning' stars:

Cb13-26 Cb13-27 Cb13-28 Cb13-29 Cb13-30 Cb14-1

109 110

Cb14-2 Cb14-3 Cb14-4 Cb14-5 Cb14-6 Cb14-7 (336)

111 112

Cb14-8 Cb14-9 Cb14-10 Cb14-11 Cb14-12 Cb14-13

113 114

Cb14-14 Cb14-15 Cb14-16

115

Cb14-17 Cb14-18 Cb14-19 (348)

348 / 3 = 116 = 4 * 29

Metoro seemed to able to read these glyphs. At Cb13-30 he saw a tamaiti, and 13 * 30 = 390 = 368 + 22. The day number with 3 glyphs per day counted from Cb1-1 is 110, seemingly short for 11 ('one more') and sun (10).

Hau tea with two eyes identifies a pivotal point in the calendar, and 13 * 28 = 364 = 390 - 26 = 30 * 13 - 2 * 13.

At Cb14-2 Metoro said tatagata ariga erua, and indeed we can see a variant of ariga erua. The front head has an eye, but not the left one.

Manu kake at Cb14-15 has his wings flapping. The 'deluge' (Cb14-17) comes in the last day.

side a	side b
392	102		240		4
		Cb5-9		Cb14-15
		103		344

245 = 5 * 49, and 495 = 740 - 245 = 5 * 99:

392	102		240		4
		Cb5-9		Cb14-15
*495 = 5 99 = 5 * (50 + 49)**			*245 = 5 49**
*250 + 2 245 = 740**

This perceived structure indicates we should search for glyph number 250 counted from Ca1-1. The glyph is Ca9-22 (at position 20 among 28 below):


Ca9-3	Ca9-4	Ca9-5	Ca9-6	Ca9-7	Ca9-8

Ca9-9 (237)	Ca9-10	Ca9-11	Ca9-12	Ca9-13	Ca9-14

Ca9-15	Ca9-16	Ca9-17	Ca9-18	Ca9-19	Ca9-20

Ca9-21	Ca9-22 (250)	Ca9-23	Ca9-24	Ca9-25	Ca9-26

Ca9-27	Ca10-1	Ca10-2	Ca10-3 (258)

The last of the 28 has a sign with a reversed 'deluge', and maybe it means land is rising again, 8 glyphs beyond number 250.

258 / 3 + 64 = 150. The 2nd half of 300 could be ending with Ca10-3 (10 comes first in 10 * 3 = 30).

Koti at Ca9-9 (note 99 as if an allusion to Venus - also in 495 = 5 * 99) should mean it is a time of darkness at that spot. And indeed it is if it is day 237:


Gb1-6	Gb1-7 (237)

But then we should add 64, and 237 + 64 = 301 = 'one more' than the apportioned time for sun.

And Ca9-22 will be at day 314:


Ca9-22 (314)	Ca9-23	Ca9-24

Then we of course must look at glyph number 64 from the end of side b, and it ought to be in line b12:

b1	24	348	24
b2	25	324	49
b3	22	299	71
b4	23	277	94
b5	21	254	115
b6	29	233	144
b7	27	204	171
b8	29	177	200
b9	30	148	230
b10	22	118	252
b11	22	96	274
b12	25	74	299
b13	30	49	329
b14	19	19	348

64 - 49 = the difference between 8 * 8 and 7 * 7 = 15, and 25 - 15 = 10:


Cb12-5	Cb12-6	Cb12-7	Cb12-8	Cb12-9 (675)	Cb12-10

Cb12-11	Cb12-12	Cb12-13	Cb12-14	Cb12-15	Cb12-16

Cb12-17	Cb12-18	Cb12-19	Cb12-20

A mago, of course! But it is glyph number 676 from Ca1-1, which means it comes immediately before the first of those 64 glyphs. 676 + 64 = 740.

There may be some trouble with 740, similar to Gb8-30 which needs to be counted twice (and Ha1-1--3 which should not be counted at the beginning). If there is some glyph beyond Cb12-10 which needs to be counted twice mago will be in his right position.