Studying the new map we quickly will discover 360 days from day number 17 to day number 377:

Glyph numbers and days below are counted from Hb9-48.
			48
Hb9-45	Hb9-46	Hb9-47 (1296)		Hb10-31	Hb10-32	Hb10-33 (51)
1296 / 3 = 432			16	51 / 3 = 17
			21
Hb6-38	Hb6-39	Hb6-40 (1131)		Hb7-8	Hb7-9	Hb7-10 (1155)
377			7	385

Glyph numbers below are counted from Hb9-48.
			1077
Hb10-31	Hb10-32	Hb10-33 (51)		Hb6-38	Hb6-39	Hb6-40 (1131)
0			359	360 = (1131 - 51) / 3

Having discovered this, we of course must also try with day number 385 in a similar way. If tapa mea kai in Hb10-32 marks a day zero, then also tapa mea kai in Hb7-9 ought to be a day zero.

If we continue to the end of side b from Hb7-10 there are (1296 - 966) / 3 = 110 days. Side a has 648 / 3 = 216 days. 110 + 216 = 326 days. Therefore only 359 - 326 = 33 days remain (of those 359) and they should be at the beginning of side b. 3 * 33 = 99 glyphs.

To reach glyph number 99 counted from the beginning of side b we quickly find the last glyph in line Hb2, i.e. day 360 will be where glyph line Hb3 is beginning:

Glyph numbers below are counted from Ha1-1.
Hb3-1	Hb3-2	Hb3-3 (750)	Hb3-4	Hb3-5	Hb3-6
313 = (750 - 3) / 3 + 64			day 314 from Friday

Glyph number 750 counted from Ha1-1 is a honu flanked (to mark his importance) by two exactly alike tagata rere glyphs. We have been here before, but then we counted from Ha1-4 and ended up at Hb3-6 (in day 314 counted from Friday).

750 + 1296 = 2046, and 2046 - 966 = 1080, i.e. day number 360 counted from tapa mea kai in Hb7-9:

Glyph numbers below are counted from Ha1-1.
			1077
Hb7-8	Hb7-9	Hb7-10 (966)		Hb3-1	Hb3-2	Hb3-3 (750)
0			359	360 = (750 + 1296 - 966) / 3

To synchronize we ought to count from Hb9-48 instead:

Glyph numbers below are counted from Hb9-48.
			1077
Hb10-31	Hb10-32	Hb10-33 (51)		Hb6-38	Hb6-39	Hb6-40 (1131)
0			359	360 = (1131 - 51) / 3

Glyph numbers below are counted from Hb9-48.
			1077
Hb7-8	Hb7-9	Hb7-10 (1155)		Hb3-1	Hb3-2	Hb3-3 (939)
0			359	360 = (939 + 1296 - 1155) / 3

The text of Q cannot take part in this game, because only Hb3-1--3 is within its limit. Already Hb6-38--40 is outside the reach of the Q text.

If we begin from Hb9-48 (in Friday), the order must be as above, where we first encounter Hb10-31--33 (after 16 days), then move a year (360 days) forward, to day 16 + 1 + 360 = 377 from Friday.

The central glyph in day 377 from Friday is a koti glyph, and 13 * 29 = 377. A new year will then begin after a week + 1 day. 16 + 1 + 360 + 7 + 1 = 385 from Friday. 11 * 35 = 385.

This new year stretches for 360 days and ends up at honu in Hb3-3 (939), after having passed both Hb9-48 and Hb10-31--33:

Glyph numbers and days below are counted from Hb9-48.
			48
Hb9-45	Hb9-46	Hb9-47 (1296)		Hb10-31	Hb10-32	Hb10-33 (51)
1296 / 3 = 432			16	51 / 3 = 17
			1077
Hb10-31	Hb10-32	Hb10-33 (51)		Hb6-38	Hb6-39	Hb6-40 (1131)
17 = 16 + 1			359	360 = (1131 - 51) / 3
			138
Hb7-8	Hb7-9	Hb7-10 (1155)		Hb9-45	Hb9-46	Hb9-47 (1296)
385 = 360 + 24 + 1			46	432
			885
Hb10-31	Hb10-32	Hb10-33 (51)		Hb3-1	Hb3-2	Hb3-3 (939)
449 = 432 + 16 + 1			295	745 = 385 + 360