Qa2-113	Qb3-11	Qb3-13	Qb5-112	Qb5-123	Qb7-115

Maybe these can be used in finding out what ariga erua means.

Q is the shortest of the three parallel texts (H / P / Q). But it is not in as good a condition as H and P.

The Q text follows the other two up to a major break in time, illustrated by moe followed by double toga glyphs (in H and P):

Hb6-26	Hb6-27	Hb6-28	Hb6-29	Hb6-30	Hb6-31	Hb6-32 (934)
			-	-
Pb8-7	Pb8-8	Pb8-9			Pb8-10	Pb8-11 (938)
						...
Qb9-105	Qb9-106	Qb9-107	Qb9-108	Qb9-109	Qb9-110

Hb6-33	Hb6-34	Hb6-35	Hb6-36		Hb6-37		Hb6-38
Pb8-12	Pb8-13	Pb8-14	Pb8-15	Pb8-16	Pb8-17	Pb8-18	Pb8-19	Pb8-20

There are no ariga erua glyphs visible beyond line Qb7, and there is only one (with special characteristics, on side a):

Qa2-113
Qb3-11	Qb3-13	Qb5-112	Qb5-123	Qb7-115

Beyond the point where the text of Q is ending there are 2 parallel ariga erua glyphs in H and P:

On side a there are more than one ariga erua glyph in H and P. Below I have ordered them in parallel:

To continue on side b (as far as the text of Q stretches):

Returning to the ariga erua glyphs in Q we now know there could once have been two more on side b, but hardly any more on side a:

								...			..
Qa2-113		Qb3-11	Qb3-13		Qb5-112	Qb5-123			Qb7-115

Furthermore, we can see a tendency of pairing in the center of the table above, but presumably the idea was to have single ariga erua glyphs at the the beginning and end.

Next, if there once was 8 ariga erua glyphs, then the eyes seem to disappear after the first 4 of them. The place where this happens should be studied:

Qb5-112	Qb5-113	Qb5-114	Qb5-115	Qb5-116	Qb5-117
Qb5-118	Qb5-119	Qb5-120	Qb5-121	Qb5-122	Qb5-123

Immediately before there are double toga glyphs (as immediately beyond the end of the Q text):

...
	Qb5-101	Qb5-102	Qb5-103	Qb5-104	Qb5-105
Qb5-106	Qb5-107	Qb5-108	Qb5-109	Qb5-110	Qb5-111

Maybe 3 glyphs are missing at the beginning of line Qb5 (judging from the drawing of the line in Barthel). If so, then the double Rei in Qb5-107 would be *Qb5-10 and the pair of toga have ordinal numbers -13 and -14.

Ariga erua in Qb5-112 would be -15 and ariga erua in Qb5-123 would be -26, plausible numbers, I think. (Hb2-30 and Pb4-52 have twice 15 respectively twice 26.)

Qb5-117 has at right a honu (vae kore) and it could indicate a solstice. Niu glyphs come after the 10 glyphs defined by the pair of ariga erua:

*Qb5-27	*Qb5-28	*Qb5-29	*Qb5-30	*Qb5-31	*Qb5-32
*Qb5-33	*Qb5-34
*Qb5-35	*Qb5-36	*Qb5-37	*Qb5-38	*Qb5-39	*Qb5-40
*Qb5-41	*Qb5-42

Here I have guessed there are 3 glyphs before vae kore in  Qb5-101, and reconstructed ordinal numbers from that. Notably honu is at *Qb5-36. There are 8 + 8 = 16 glyphs from mago at Gb5-27 to the end of line Qb5.

The mago has an empty hand - he is finished with his dark half year. We can see a pau sign at right in Gb5-34. In Qb5-38 the legs are fat and the 2 limbs towards right are vanishing, while in Qb5-39 the new 'beast' arriving has a single 'limb' at left. Several signs indicate a turnover at winter solstice from the dark back side of the year to the light front side.

The break in time between Qb5-38 and Gb5-39 cannot be more clearly illustrated. The parallel texts are not quite so outspoken:

	-
Hb3-2		Hb3-3 (750)	Hb3-4	Hb3-5	Hb3-6
Pb5-7	Pb5-8	Pb5-9 (764)	Pb5-10	Pb5-11	Pb5-12
	-
*Qb5-35		*Qb5-36	*Qb5-37	*Qb5-38	*Qb5-39

Honu in Hb3-3 has ordinal number 750 counted from Ha1-1. The break in time would accordingly occur in day number 251 (= 752 / 3). Counting from Ha1-4 changes the day number from 251 to 250, and would also result in honu receiving day number 249 (and 24 * 9 = 216).

But if we change from Ha1-1 to Ha1-4, it would be natural to also add 64, which will put the break in time at 250 + 64 = 314, which indeed seems perfect. In G, we know, it would be at Gb1-20 (or at Gb1-21 if we count from Ga1-1):

Gb1-21 has more in common with Qb5-38--39, it exhibits a kind of split. In P the break occurs between glyph numbers 766 and 767 (counted from Pa1-1). Expressed in days (given 3 glyphs per day) it will be in day 256 (766 / 3 = 255⅓). 256 = 4 * 64.

To reach day 314 also in P, we must begin 58 days earlier than at Pa1-1 (not far from 59 from tamaiti at Gb7-3 to the end of side b, and 58 it becomes if we do not count Gb8-30 twice). And Gb1-20 will be day number 314 if we count from Ga1-1 and add 64.

We must investigate the location of mago mea in P:

Hb9-60	Hb9-61	Hb9-62	Hb9-63	Hb9-64	Hb9-65
432			1
*Pb11-7	*Pb11-8	*Pb11-9	*Pb11-10 (1108)	*Pb11-11	*Pb11-12
369			370

There are 599 + 559 = 1158 glyphs in the P text. If we divide by 3 it presumably becomes 386 days.

From mago mea to the end of side b there are 386 - 369 = 17 days (51 glyphs).

432 - 386 = 46 days could be the difference between H and P.

I have come to realize that 46 may have its origin in 400 - 354. Beyond the end of the lunar calendar (based on 12 * 29.5 nights) there must come a 'crack in time' consisting of 46 dark nights. Similarly 400 - 364 engenders a crack with 36 dark nights.

A break in time is illustrated in Pb11-11. The tail in mago looks as if it signified the 'white moon half of the year' (cfr the legs in Qb5-38).

In order to begin 58 days before Pa1-1 we need to seek a glyph which lies 3 * 58 = 174 glyphs before the end of side b:

60 (b11) + 56 (b10) + 50 (b9) = 166, and 174 - 166 = 8. In line Pb8 there are 65 glyphs, 65 - 8 = 57:

Pb8-46 (973)	Pb8-47	Pb8-48	Pb8-49	Pb8-50	Pb8-51
325			326
Pb8-52	Pb8-53	Pb8-54	Pb8-55	Pb8-56	Pb8-57 (984)
327			984 / 3 = 328 (= 386 - 58)
Pb8-58	Pb8-59	Pb8-60	Pb8-61	Pb8-62	Pb8-63 (990)
329			330

Maybe Pb8-62 has a sign of ariga erua?