TRANSLATIONS

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The maze of strange numerical coincidences is difficult to handle. Let us therefore repeat what the glyphs tell, viz. that Aa6-55 depicts the end of a first cycle and that the fish is devoured by ika hiku in Aa6-67. The 'mouth' is presented in Aa6-63:

 

Aa6-55 (1) Aa6-56 Aa6-57 Aa6-58 Aa6-59 Aa6-60
Aa6-61 Aa6-62 Aa6-63 (9) Aa6-64 Aa6-65 Aa6-66
Aa6-67 (13) Aa6-68 Aa6-69 Aa6-70 Aa6-71 Aa6-72
Aa6-73 Aa6-74 Aa6-75 Aa6-76 Aa6-77 Aa6-78 (24)
Aa6-79 Aa6-80 Aa6-81 Aa6-82 Aa6-83 Aa6-84 (30)

As next step we can count and find Aa6-55 to be glyph number 471 from Aa1-1. It cannot reasonably be a coincidence that it is the same number as the number of glyphs on the G tablet.

Dividing by 2 to translate glyphs into days, we get 235.5. This means we probably should begin counting from the last glyph on side b (as in the G text).

Aa6-69 (the 15th glyph from Aa6-55) has a head tumbling down as in Gb1-7:

 

Aa6-69 Gb1-7

Therefore, it is probable that the translation of 2 glyphs into 1 day in A is correct, that the first half of the calendar cycle ends after 236 days, and that the second half of the calendar begins with Te Pei.

Ika hiku presumably is marking where a new season is beginning. Aa6-67 has ordinal number 484 counted from Ab8-84. 484 resembles 8-84, and can be imagined as 4 * 84 = 336 glyphs (or 168 = 12 * 14) days.

We have established a good ground for continuing by comparing A with G and K. But we will wait with that and instead have a look at P, where there are two obvious ika hiku glyphs:

 
Pa6-44 Pa11-27

If Te Poko Uri is alluding to puoko (head), then his season possibly ends with two tails 'back-to-back' is an inversion of the Janus heads. It must be tails because the uri season is ending.

The season which comes after uri should then also end at Te Pei. If we read as the sun, moving from the beginning of side a to its end, and then turn the tablet to read on side b, we must continue to move from east to west - not according to the movement of the kuhane. We have to begin at the end of side b (One Tea in G) and move to its beginning, at Te Pei).

For the sun Te Pei at the beginning of side b (in G) is a kind of 'tail', also the end of side a. There are two 'tails' meeting at Te Pei. That is why the sun fish is being devoured by ika hiku in Aa6-67.

Now, to P:

 
a1 53 b1 25
a2 59 b2 36
a3 62 b3 39
a4 61 b4 56
a5 80 b5 50
a6 60 b6 59
a7 58 b7 63
a8 55 b8 65
a9 42 b9 50
a10 36 b10 56
a11 33 b11 *60
sum 599 sum *559

599 + 559 = 1158 = 8 * 144.75 - a number close to 144.625, we remember:

 

1154
Aa8-76 (1) Aa8-77 Aa6-66 Aa6-67 (1158)
1158 = 8 * 144.75

In A, with 1334 glyphs, we tried to reach a better number by adding 10 glyphs - 8 * 168 = 1344. Aa8-76 is number 10 from the end of side a and if counted twice the total number of glyphs in A will be 1334 + 10 = 1344.

Here, in P, another situation rules, where we rather should take away 16 * 0.375 = 6 glyphs to reach 16 * 72 = 1152 as a beautiful total:

 
G 16 471 + 1 29.5 8 59
K 16 192 12 8 24
A 16 1334 + 10 84 8 168
P 16 1158 72.375 8 144.75
P 16 1158 - 6 72 8 144

The glyphs in line b11 are restored as *60, but is impossible to reduce them to *54.

Possibly we should add 2 to reach 1160, because 20 * 58 = 1160, i.e. 40 months à 29 days:

 
G 16 471 + 1 29.5 8 59
K 16 192 12 8 24
A 16 1334 + 10 84 8 168
P 40 1158 + 2 29 20 58

Viri glyphs govern counting by 29 and it is not impossible to have 29 govern the total number of glyphs in the text of P.

 
a1 53 315 b1 25
a2 59 b2 36
a3 62 b3 39
a4 61 b4 56
a5 80 b5 50
a6 60 44 b6 59
16
a7 58 b7 63
a8 55 b8 65
a9 42 b9 50
a10 36 b10 56
a11 33 27 b11 *60
6
sum 599 sum *559

315 + 44 = 359 is the ordinal number for one ika hiku and 599 - 6 = 593 for the other (both numbers counted from Pa1-1):

 
2 233 6 + 559 + 358 = 923
Pa6-44 Pa11-27
361 595
1158 = 8 * 144.75

I have added 2 glyphs at the beginning of side a or at the end of side b to reach 20 * 58 = 1160 glyphs.

Beyond Pa11-27 comes 6 glyphs which could refer to those 6 we earlier speculated should be dismissed from the counting:

 
Pa11-24 Pa11-25 Pa11-26 Pa11-27 Pa11-28 Pa11-29 Pa11-30
Pa11-31 Pa11-32 Pa11-33 Pb1-1 Pb1-2 Pb1-3 Pb1-4

Both ika hiku occur on side a, and if we discard side b we get relevant results:

 
233 6 + 358 = 364
Pa6-44 Pa11-27
359 593
599

The text of side a presumably has 364 + 236 = 600 glyphs - counted from the last glyph on side b:

*Pb11-55 *Pb11-56 *Pb11-57 *Pb11-58 *Pb11-59 *Pb11-60