TRANSLATIONS

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3. The number of sun is 6. If the Pleades are regarded as a constellation with 6 stars, and if they announce a soon to come solstice (maybe both solstices), then, in order for the double maitaki sign to represent Tauono, there should be 6 'stones':

The vertical line through maitaki could mean that each 'stone' is a double-month. A regular solar year has 6 * 60 = 360 days.

Another possibility is that the vertical line has at left 3 sequential periods and at right another sequence of 3 periods, i.e. 6 periods which are ordered by the string rather than by the 'stones'. This possibility may have been used in e.g. Ka4-8, where the 'stones' at left appear to be different from those at right:

4
Ka4-8 Ka4-9 Ka4-10

The 'stones' presumably represent two periods, but we can only see half of each such period, represented by a semicircle. Such semicircles appear in other glyph types too, for instance at the top respectively the back of the head in Aa7-8 and Aa7-11:

Aa7-8 Aa7-9 Aa7-10 Aa7-11

A twin pair of semicircles can also be seen at right on the uplifted arm in Aa7-11.

4. The two sides of maitaki are often - as just has been exemplified - assymmetric. It means we should regard them as qualitatively different.

There is a very old picture (ref. Campbell 2) showing how at the time of new year (the Sed Festival) the ancient Pharaohs had to visit the sanctuary of the wolf-god Upwaut, the 'Opener of the Way', and in the old picture we can recognize the same triplets of 'half-stone' signs as in maitaki:

The right (future) version of Pharaoh is in the sanctuary of Upwaut, which is located between the sets of 'half-stones'. The black ball probably represents, I think, a symbol designed after the black new moon. In ancient Egypt there were 5 'black' days between the last day in the calendar (360) and day 1 of next year.

My interpretation of the picture is that the old year is represented by the 3 units formed like buns at left and the new year by those at right. A glyph in the 24th and last period of a calendar for the year in Keiti is designed very much in the same way and it evidently stands at winter solstice:

 
Eb5-29 Eb5-30 Eb5-31
Eb5-32 Eb5-33 Eb5-34
Eb5-35 Eb6-1 Eb6-2

5. The Pleiades cannot be observed at all times. Makemson says that 'thirty or forty days' after their disappearance 'in the rays of the setting Sun toward the end of April' the Pleiades 'are visible on the eastern horizon just before dawn':

 

30-40 days invisible April/May Matariki i raro
heliacal rising June
start for ritual calendar July
rising in the evening November Matariki i nika
new year November/December

It is not clear if also on Easter Island they defined periods Matariki i nika and Matariki i raro by observations in the evening, or in the early morning. In the latter case the table above is wrong. Likewise, of course, if they did not use the concept at all.

If they watched the Pleiades both in the morning and in the evening, it is conceivable that they had a new year which began according to evening observations and a ritual calendar which began according to morning observations.

The rays from the sun 'kills' a part of the cycle of the constellation. The stars are there, but cannot be seen. It is very much like when the new moon is still dark because it is in the sight line between the observer and the sun, bathing in 'vaiora a Tane'.

Otherwise a star or constellation can be observed during half a year (given a fixed time in the night for the observations), from its appearance in the east to its disappearance in the west. It takes ca 2 quarters (182 days) to travel 180º.

Once there were 13 constellations in the zodiac, but one was eliminated (the Serpent). If we count 12 / 13 of 182 days we get 168, an important number in the rongorongo texts. Maybe the period of invisibility was regulated to be 182 - 168 = 14 days. Twice that comes not far from Makemson's estimate 30 - 40 days.

Another alternative would be to stipulate 32 days' invisibility:

 

182 168 14 28
182 167 15 30
182 166 16 32

Te Pou (Sirius) is located at 9 * 29.5 = 265.5 (or rather day number 266) and 100 days later the solar year is ending at 365.25 (or rather day number 366). The redmarked alternative with 32 days of invisibility and 166 days of visibility is to prefer because of the harmony. And the ancient Egyptians associated the reappearance of Sirius with new year.

The qualities of 166 and 168 are different. If 182 = 14 + 168, then the moon seems to be in focus. If 182 = 16 + 166, then Sirius. Only 182 = 15 + 167 obviously refers to the sun.

28
Ga6-24 Ga6-25 (166) Ga6-26 (167)
29
Ga6-27 (168) Ga6-28 Ga6-29

The figure in Ga6-28 (where 6 * 28 = 168) could refer to the invisible phase - there are no 'eyes'. The period is number 29.

In K there is an interesting maitaki glyph to study:

29
Kb4-10 Kb4-11 Kb4-12 Kb4-13 (166) Kb4-14 (167)
30
Kb4-15 (168) Kb4-16 Kb4-17 Kb4-18 Kb4-19

Kb4-13 has a variant of the hand gesture 'waving goodbye' (or 'handing over') connected to maitaki. Could it mean that the season of maitaki is ending? The similar hand gesture in p.m. supports this interpretation:

Aa1-30

5 + 5 = 10 glyphs distributed in periods 29-30 should be compared with 3 + 3 = 6 glyphs in periods 28-29 in G, and we can see the parallel Kb4-14 and Kb4-19 as the 'end of sun on the island' respectively the 'head containing new life'. Tamaiti in Kb4-15 (and period 30) comes in the 'new life' period, and with 168 indicating moon that is correct - 30 is one night beyond the black number 29.

Aa1-30 is also one more than 29. Maybe Kb4-13 is the beginning of a new season (without maitaki):

50 90 25 22
Ka1-24 Ka4-8 (75) Kb4-13 (166) Kb5-20 (192) Ka1-1
52 52 23
192

If there are 2 days for each glyph, then 91 glyphs of maitaki (from Ka4-8 to Kb4-13) will be 182 days. And the rather meaningless 23 glyphs at the end will be a meaningful 46 days.

Possibly we should read Kb5-15 (with ordinal number 187 and - maybe - day number 374) as a 4th and final maitaki glyph. 5 * 15 = 75 = the ordinal number for Ka4-8 (with 4 * 8 = 32):

50 90 20
Ka1-24 Ka4-8 (75) Kb4-13 (166) Kb5-15 (187)
52 = 4 * 13 22
164 = 8 * 8 + 100

192 will then be equal to 8 * 8 + 100 + 28.

...
Kb5-10 Kb5-12 Kb5-13 Kb5-14 Kb5-15 Kb5-16 Kb5-17
364 368 370 372 374 376 378
182 184 185 186 187 188 189

Kb5-10 (with 5 * 10 = 50) will be the end of the regular calendar, either with 1 day per glyph or with 2 days per glyph. Then comes a non-existent glyph, maybe a glyph which never was there, a 'black' glyph.

If the missing glyph 'carries' two days, then its absence solves the dilemma of how to illustrate 1¼ days.

In Kb5-12 there are 2 'feathers' at right as if to indicate that the 2nd cycle of the year now will begin. With 2 days per glyph it could mean that the year is beginning in the middle of the K text, with 1 glyph per day it could mean that the year is beginning at the beginning of the K text.

Kb5-14 is the last glyph in a season with 8 'feathers', we can read. But 372 / 8 = 46.5 and 186 / 8 = 23.25, which seems odd. Maybe there is a reference to Kb5-12 (where 368 / 8 = 46). 184 / 8 = 43 is not equally good, indeed rather bad. Therefore we presumably should count with 2 days per glyph.

Kb5-14 can also be read as 12 * 31 = 372. In that case Kb5-15 needs a new light, with (maybe) both sun (5) and full moon (15) present.