TRANSLATIONS

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Now, let us continue with the glyph dictionary. We made a long detour to investigate manu kake, and it paid off. We are ready for next page:

 

A waning moon sign is located at top right in Ka4-11:
5
Ka4-11 Ka4-12
Ga3-20 Ga3-21

The parallel sign in Ga3-20 is a waxing sun sign. The sun light is gaining in strength and the moon light is - comparatively seen - diminishing in importance.

For the moon concave to the left means waning in the rongorongo system, while for the sun it presumably means waxing.

If Te Pei comes before the first glyph lines on side a in K and G, and if Te Piringa Aniva should be located in line a1, then - we have seen in K - there is a gap to be bridged before the arrival of Te Puoko Uri:

 
20 12
Ka2-1 Ka2-22 Ka3-1 Ka3-14 (60)
1 * 22 14
42 67 19
Ka3-15 Kb1-7 Kb4-19 Kb5-20
2 * 22 4 * 22
Te Piringa Aniva (29.5)
...
*Ka1-17 *Ka1-18 *Ka1-19 *Ka1-20 *Ka1-21 *Ka1-22 *Ka1-23 *Ka1-24
Ka2-1 Ka2-2 Ka2-3 Ka2-4 Ka2-5 Ka2-6 (30) Ka2-7 Ka2-8
Ga1-24 Ga1-25 Ga1-26 Ga1-27 Ga1-28 Ga1-29 (30) Ga1-30 Ga2-1 (32)

Ka1-23 is the glyph wich follows the 22nd glyph, which we now understand means a cycle has been completed (yet another hidden 22). The 'net' in G built from the measure 59 (nights in a lunar double- month) is in K constructed from a more mathematical 'net' based on 7 * π.

In K there are 97 glyphs on side a, equal to - I believe - 2 * 97 = 194 days. In G there are 229 glyphs (days), to which we should add Gb8-30.

230 is less than 8 * 29.5 = 236, and there is no room for 8 kuhane stations on side a of G. But 10 * 23 is exactly right. Is there a sun measure competing with the kuhane 29.5 measure? 8 * 23 = 184 could refer to half a solar year. The 4 extra days between 364 and 360 could be located anywhere, equally well at the end of the front cycle.

8 * 22 = 176 (60 less than 236 and 16 less than 192), but - we have concluded - Te Pei is glyph number 7 (14 days in) on side b. The 8th island is difficult to find on side a.

192 - 184 = 8 glyphs = 16 days. At Nga Kope Ririva there are 20 glyphs (including the vacant space between the mainland and the three rocks, but they cannot be equal to (184 - 180) + 16, because we cannot mix glyphs and days:

 
1 16
Kb5-2 Kb5-19 Kb5-20

184 days is in K equal to 92 glyphs, I assume. 192 = 100 + 92, or expressed in days 384 = 200 + 184.

From Te Pou to the end of the year, we have concluded earlier, there are 100 days. Maybe they are equal to the latter half of 200 days. The way up the mountain is the way down.

24 24
Ka4-13 Ka4-14 Ka4-15 Kb1-11 Kb1-12 Kb2-14 Kb2-15
80 81 82 107 108 133 134
52

With 7 * π as the measure (i.e. 22) we have located 7 such groups of glyphs (= 154 glyphs = 308 days) beyond line Ka1. But between the 1st and the rest (6) of them there is a gap which ends with sun regenerated. There are 14 glyphs (28 days) in this gap. 1 * 22 + 14 + 6 * 22 = 168 (or 336 days).

20 12 42 67 19
22 14 44 88
168

168 = 182 * 12 / 13. Or expressed in days: 336 = 364 * 12 / 13. We now know what glyph line a1 stands for, it is the 13th special season, which is outside the regular calendar.

22 20 12 130
Ka1-1 Ka1-24 Ka2-1 Ka2-22 Ka3-1 Ka3-14 Ka3-15 Kb5-20
24 22 14 132
2 * 24 = 48 days 168 * 2 = 336 days
2 * 192 = 384 days