TRANSLATIONS

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The uplifted sun fruit in Qa8-47 (an orange maybe), is a vai sign located above the normal position:

Qa8-46 Qa8-47 (342) Qa9-1 Qa9-2
342 / 2 + 64 = 235 236
Qa9-3 Qa9-4 (346)
237

This sign we have met before, at Ca9-4 (where 9 * 4 = 36 resembles Qa9-4).

346 can be read as 3 * 46 = 6 * 23 and will then be the reversal of 236.

If we wish to have sun ascend after 10 months, then day 235 is not enough. We need to add another 64 days.

There are 736 glyphs in Q, and from *Qb5-35 to the end of side b there are 128 glyphs = 64 days:

*Qb5-33 *Qb5-34 (608) *Qb5-35 *Qb5-36
day 368 = 608 / 2 + 64 day 1

One way to accomplish another 64 days is to count each glyph from *Qb5-35 as 1 day. But why should we do that?

Another alternative is to search for glyph number 608 - 128 = 480, in order to begin counting from there:

Qb2-30 Qb2-31 Qb2-32 Qb2-33 Qb2-34 Qb2-35
299 300 301
Qb2-37 Qb2-38 Qb2-39 Qb2-40 Qb2-41 Qb2-42 (480)
302 303 480 / 2 + 64 = 304 = day 1

Here we have been before:

80
Qb1-1 (388) Qb2-31 Qb2-32 Qb2-34 Qb2-35 (472)
258 40 days 299 day number 300 (= 236 + 64)

At that time tamaiti at Qb2-31 was found to allude to day 231 (defined by 472 / 2 = 231 in hau tea 4 glyphs later). There seems to be a rule that we must count to 4 at cardinal points. Therefore Qb2-42 will not be at day 300 but at day 304.

Qb2-42 appears to be a new point from which to count, we discovered earlier. It comes after 42 days have elapsed from the beginning of side b. 472 - 387 = 85, and haś in Qb2-34 is the last glyph of 84 from Qb1-1.

Earlier we thought Qb2-35 should be given day number 231 (not 236), by cause of 11 * 42 / 2 = 231. It would so to say represent the point where the G tablet is turned around. It would be day 231 + 64 = 295.

This assumption gave good results:

Qb3-1 Qb3-2 (486) Qb3-3 Qb3-4 Qb3-5 Qb3-6
234 (307) 235 (308) 236 (309)
Qb3-7 Qb3-8 Qb3-9 Qb3-10 Qb3-11 Qb3-12
237 (310) 238 (311) 239 (312)
Qb3-13 Qb3-14 Qb3-15 Qb3-16 (500) Qb3-17 Qb3-18
240 (313) 241 (314) 242 (315)
Qb3-19 Qb3-20 Qb3-21 (505) Qb3-22 Qb3-23 Qb3-24
243 (316) 244 (317) 245 (318)
Qb3-25 Qb3-26 Qb3-27 Qb3-28 Qb3-29 Qb3-30
246 (319) 247 (320) 248 (321)
...
Qb3-31 Qb3-32 *Qb3-33 *Qb3-34 *Qb3-35 *Qb3-36 (520)
249 (322) 250 (323) 251 (324)

Numbers withing parenthesis are the normal ones, e.g. 506 / 2 + 64 = 317 at ua (Qb3-21).

If Qb2-42 is regarded as day 231, i.e. the first on the 'back side', then we can count twice 64 days and add to the number of days from Qa1-1 in order to reach 10 months at hua reva:

596
Qb2-41 Qb2-42 (480) Qa8-46 Qa8-47 (342) Qa9-1 Qa9-2
11 * 42 / 2 = 231 = day zero 298 128 + 342 / 2 = 299 300 = day zero

This model will give the 'front side' 300 days, and Qa9-1 will be the first glyph beyond that and a new vai comes a day after:

Qa9-3 Qa9-4 (346)
day 1

I think we have proven that hua reva is a symbol for the last day of a period of 10 months.

The kuhane station Hua Reva must have this name because it is the 10th station. There is no necessary connection with what happens out in mother nature.

A fruit (hua) is laden with juice and the vai glyph type is suitable, especially as it can be drawn to resemble a citrus fruit.