7. In the chapter Hamal it was noted that Regulus was one of 10 stars which maybe could be associated with the 10 antediluvian kings:

... Brown associates it with Aloros, the first of the ten mythical kings of Akkad anterior to the Deluge, the duration of whose reigns proportionately coincided with the distances apart of the ten chief ecliptic stars beginning with Hamal, and he deduces from this kingly title the Assyrian Ailuv, and hence the Hebrew Ayil; the other stars corresponding to the other mythical kings being Alcyone, Aldebaran, Pollux, Regulus, Spica, Antares, Algenib, Deneb Algedi, and Scheat ...

Antares was another such star, it was said. Let us measure the current distance from Regulus to Antares and then compare with the length of reigns in the king lists. First we should put Regulus not only in its own position in the sky but also at the position of Achird, because 266 + 153.7 = 419.7 and Achird can be imagined as the star where Regulus 'is buried' (puo, 'hilled up'):

86 140
Ga4-3 Ga4-4 Ga4-5 (*153) Ga4-6 (90)
    Regulus (153.7 - 92 = 61.7)
230
35 152 52
Gb2-10 (266) Gb7-8 (419) Gb7-9
autumn equinox Achird (11.7)
242

The logic of referring to Regulus also at Achird is based on the knowledge that autumn equinox on Easter Island is equal to spring equinox north of the equator.

Maybe side b is longer than side a because summer is longer north of the equator. 30 is a number of Jupiter (Father Sun) and 42 (twice 21) is the number of assessors in the Underworld (the night side). Thus the G tablet can be said to have 72 (= 360 / 5) + 400 glyphs.

Next we should put also Antares in double positions (which we did already in the Achird chapter):

... If we count 266 + 250.1 = 516.1 for Antares, reaching out for his day number beyond the previous winter solstice, we ought to find him at glyph number 516.1 - 472 = 44.1:

Aldebaran 179 Antares
Ga1-3 (*68) Ga1-4 (5) Ga7-15 (185) Ga7-16 (*250)
Aldebaran α Tauri 04h 33m (4 * 60 + 33) / 1440 * 365¼ = 69.2
Antares α Scorpii 16h 26m (16 * 60 + 26) / 1440 * 365¼ = 250.1
Ga2-13 (44) Ga2-14 (**517) Ga2-15 Ga2-16 (*111) Ga2-17

The resemblance between mago in Ga2-14 and mago in Ga7-16 ought to indicate a similarity in character - and they could both represent Antares.

The mouth of mago in Ga2-14 is closed and a single rising feather is at left inside his head, probably meaning 'not visible'. The parallel with Gb7-8, where Regulus presumably is hidden by the world mountain, is obvious ...

We had better work this out once more:

185 43
Ga7-16 (*250) Ga7-17 (187)
Antares (250.1 - 92 = 158.1)
230
35 205
Gb2-10 (266)
autumn equinox
242
43 185
Ga2-13 Ga2-14 (45)
'Antares' (266 + 250.1 - 472 = 44.1)
230

Not only are the mago glyphs basically alike but also the numbers are striking, with 185 and 43 on one hand and with the same numbers in the opposite order on the other. The closed mouth on side b ought to refer to the back side of the sky, where time in a way runs in the opposite direction.

186 (from Ga2-13) + 36 (Gb2-10) = 222. Therefore we should be able to count 222 from Ga7-16 and find spring equinox: 186 + 222 = 408 and this is indeed where we have counted spring equinox to be north of the equator.

Question now is what the distance from Regulus to Antares could be. There are two possibilities:

88 95 43
Ga4-5 Ga4-6 (*154) Ga7-16 (*250) Ga7-17
Regulus (153.7 - 92 = 61.7) Antares (250.1 - 92 = 158.1)
230 = 90 + 96 + 44
35 152 52 43 185
Gb2-10 Gb7-8 Gb7-9 Ga2-13 Ga2-14 (45)
autumn equinox Achird (11.7) 'Antares' (266 + 250.1 - 472 = 44.1)
472 = 190 + (52 + 44) + 186

The measure in the king lists (cfr e.g. in Argo Navis) should therefore be 96,000 or similar:

Sumerian W-B. 144

1 Alulim 28,800
2 Alagar 36,000
3 Enmenluanna 43,200
4 Eumengalanna 28,800
5 Divine Dumuzi 36,000
6 Ensibzianna 28,800
7 Enmenduranna 21,000
8 Ubardudu 18,600
9 -
10 -

Sum

241,200

Sumerian W-B. 62

1 Alulim 67,200
2 Alagar 72,000
3 Kidunnushakinkin 72,000
4 ... ? 21,600
5. Divine Dumuzi 28,800
6 Enmenluanna 21,600
7 Enzibzianna 36,000
8 Eumenduranna 72,000
9 Arad-gin 28,800*
10 Ziusudra 36,000

Sum

456,000

Berossos

1 Aloros 36,000
2 Alaparos 10,800
3 Amelon 46,800
4 Ammenon 43,200
5 Megalaros 64,800
6 Daonos 36,000
7 Euedoraches 64,800
8 Amempsinos 36,000
9 Opartes 28,800
10 Xisuthros 64,800

Sum

432,000

The Bible (King James' verison)

1 Adam 130
2 Seth 105
3 Enoch 90
4 Kenan 70
5 Mahalel 65
6 Jared 162
7 Enoch 65
8 Methuselah 187
9 Lamech 182
10 Noah: until Flood 600

Sum

1,656

* Campbell has 28,000 here, which, however, does not agree with the sum 456,000.

There is no such number in the lists, but who thought it would be easy?