6. Where can Musca Borealis be according to this perspective? I have suggested 'the First star of Musca Australis' - when culminating at midnight in January 31 - indicates the end of an old year. It should be in the domain of Saturn and, indeed, 5 * 5 = 25 (which also fits for Ga5-5 and day 260):
I have chosen μ Muscae instead of λ Muscae (culminating 3m earlier) because the letter λ presumably was used to denote a time without light. If we count from 116 at Ga5-5 to 359 at Gb5-5 the distance is 243 glyphs, and this number is perhaps expressing the idea of rau hei:
With 0h at Gb6-25 (where 62 * 5 = 310) it seems possible that the earlier glyphs - maybe beginning with the special tamaiti in Gb3-10 - are indicating heliacal descending (together with culmination at midnight) instead of heliacal rising (and culminating at noon):
Musca Borealis could be imagined to be at the other end of the sky compared to Musca Australis. Moving 90 glyphs ahead from Gb5-5 we will reach Gb8-7:
From the culmination at midnight of Musca Australis (Gb5-5) to the heliacal rising of Musca Borealis there are 90 days - or maybe 91 as in a quarter of 364 (with puo in Gb8-8 at the end). The star Bharani is the last part of Musca Borealis at 450.4. The equations of time thus could be: μ Muscae (178.8) - 228 = 0h - 49.2 = 408 - 49.2 = Bharani (450.4) - 228 =
*42 at the heliacal rising of Bharani corresponds to 42 days beyond March 21, i.e. the date could be day 144 - (472 - 450) = 122 in our calendar or May 2. |
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