1. If we count the regular solar year as 360 days long, then the distance from spring equinox to 21h is 21 * 15 = 315 days, one more than 314. If we count from the Julian year (365.25 days long), 21h will be around 21 / 24 * 365.25 = 319.6 days beyond equinox:
With 364 days in a year 21h will come 318½ days after spring equinox. Right ascension 21h can be used as a mark for where 'Land' ends, where the summer 'cycle' (north of the equator) is finished and 'Sea' (the winter 'cycle') is beginning. This Sea in front will stretch for only around 45 nights. At 21h the 'bicycle' will have a larger back wheel than front wheel:
Alternatively we recognize the existence of an equally long 'summer year' south of the equator, and then the pair of wheels will together measure slightly more than 2 * 314 = 628 days. It should be noted that the Keiti (E) tablet has a text with 628 glyphs:
Should we count with a Sun year which is 364 days long, then Sea could begin with day 365 and stretch for 628 - 364 = 264 nights. This is the 7th day of the manzil Al Baldaah ('February 4), where 136 + 264 reaches 400. The signs in the tresses of Pachamama are distributed as 214.5 + 185.5 = 400:
The Keiti text has a vacant space after glyph 260:
Fischer indicates there is also a little vacant space at the end of line a7, but I counted with neither of these empty spaces when I reached 628. Possibly *Ea8-5 - where Metoro read ki te vai (to the water) - corresponds to the first night of 'February. We might need the E text (with the words of Metoro) in order to grasp the structure of the G text. |