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This is the beginning of side b:

Side b
Almuqaddam 12 13 (337) Al Muakhar 1
April 17 (107) 18 19
Cb1-1 (393) Cb1-2 Cb1-3

107 days could have been derived from difference between 8 * 59 (= 472) and 5 * 73 (= 365), but another possibility is the difference between 471 and 364 (= 14 * 26).

471 = 1½ * 314 and 364 = 314 + 50. Therefore 471 = 314 + 50 + 107.

Turning the C tablet around to side b could be like returning to the origin. The leap year evidently has ended and the beginning of side b could correspond to the origin of the next year, which should not be a leap year.

80 Ca1-1 283 Ca11-1 (285)
March 22 (81) December 31 (365)
365
59 Ca13-2 (345) 46 *Ca14-29 (392)
February 29 (60) April 16 (472)
107
Cb1-1 (393) 347
April 17 (107)
348

I have coloured 107 black because these days contain the leap day.

I am suggesting that one of the basic cycles in the rongorongo texts corresponds to a circumference measured out by 2π:

313 ½ cycle

100 * π

49 364

314 + 50

106 471

1½ * 314

156 628

2 * 314

314 50 107 157 (= 50 + 107)

2 * 314 = 628 is equal to the number of glyph spaces I have counted on the Keiti (E) tablet.

Line Ea8 has 33 glyphs and a hole which I have counted as 1. This hole comes beyond glyph Ea8-4 (260), and 628 - 260 = 368. But probably we should not count the hole as a glyph.

When measuring time the ordinal number 1 comes not at the beginning but at the end of the beginning. Therefore the C text is not beginning at March 21 but at March 22. Likewise cannot number 628 be the number of days on the E tablet, it must be 1 less.

In C we have found the beginning of the Moon calendar arriving after glyph 156 (= 314 / 2 - 1):

An Nathra 9 (101) 10 11 12
August 25 (237) 26 27 28
Ca6-17 (157) Ca6-18 Ca6-19 Ca6-20
tagata oho rima - ki te marama koia kua oho ki te marama kua moe
μ Hydrae (157.1) no star listed Shir (158.9) φ Hydrae (160.3)

Counting from Ca6-17 (157 = 314 / 2) means half a cycle is in the past and the 2nd half cycle is beginning with day 50 * 3.14.

Each day measures π and to divide 314 with 2 gives the same result as multiplying 3.14 with 50.

In rongorongo times Algenib Persei rose precisely 50 days after March 21 (80). In my suggested 2π cycle this would correspond to 157 days. When Algenib Persei rose with the Sun in May 10 (130) it could possibly also have been when the last day of 628 ended.

Alrescha 9 10 (360)
May 10 (130) 11
Ca2-24 Ca2-25
niu - kupega hia mai tu te niu - ku huki
Algenib Persei (50.0)  

At the beginning of side b we might count 393 (Cb1-1) - 156 (Ca6-16) = 237 as a Sign that the 1st night beyond number 236 (= 472 / 2) is beginning here. However, this cannot be true because 472 is one more than 471.

Instead we should regard April 16 (*Ca14-29) as day 107 counted from January 1 in a leap year and April 17 (Cb1-1) as day 107 counted from January 1 in the following ordinary year. But in both cases the beginning of the year is not January 1 but December 31.