3. Number 168 has been mentioned earlier too (cfr at Ruhi):
... 24 hours = 360°. We can count the distance between the stars as (16 - 5 = 11 hours) + (26 - 12 = 14 minutes), or about half 360°. To be more exact: 11 + 14 / 60 = 11.23 hours = 11.23 / 24 * 360 = 168° ... ... From the appearance of Puanga to the appearance of Rehua there are ca 170 days (= 365.25 / 360 * 168) ... There are 168 glyphs on side b before Jupiter at Gb6-16 (where 61 * 6 = 366):
84 = 168 / 2 and 218 = 168 + 50. 168 = 7 * 24 (the number of hours in a week) is a suitable number for measuring 'land', ending at Jupiter (399) followed by the virgin star Spica (400). This idea maybe explains its use also here:
168 = 108 + 60 and with 108 assigned to the region of winter solstice the season with Sun present could possibly be referred to by using number 168. If we imagine 168 days on side a were used to represent Sun when south of the equator and 168 days on side b to represent Sun when north of the equator, then there will be 68 further days on each side which we need to explain; 472 = 2 * 168 + 2 * 68. 168 = 4 * 42 and 68 = 4 * 17 (i.e. 4 * 25 = 100). Lets us now try to improve our time-space model from Ana-muri to Ana-mua, which south of the equator means winter. Below I have allotted 1 rectascension minute also to Spica:
I have two names to choose between as regards Sirius, either Te Pou or Reitaga, and I have none for Toliman. Therefore I decided to use The Dog Star respectively The Mad Dog - a way to point at the possibility of these 472 days being associated with a Dog. However, Ana-mua ought to come before Ana-muri (the ship of Sun should not sail backwards). Therefore we ought to change the number for the southern winter to 39 + 91 + 472 + 109 = 711. As 'proof' I can point at 39 + 91 = 130 (= 26 * 5). But then we should also change 472 to 471, because 471 + 109 = 580 (= 29 * 20). To make the pieces of the puzzle fit I try once again to make a change at Spica, taking away her 1m, which makes sense because 'inside' (ki roto) means invisible (not possible to count):
24h = 24 * 60 = 1440m, but 728 + 130 + 581 = 1439. I have here regarded Ana-roto as a kind of 'leap day'. But such a day could alternatively be among those 109 at the end, in which case the number would be 108. 728 + 130 = 858 = 13 * 66 = 26 * (28 + 5). |
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