We recognize Aa3-6--15 because these glyphs have been studied earlier (cfr manu kake):

Aa3-6	Aa3-7	Aa3-8	Aa3-9 (184)	Aa3-10
Aa3-11	Aa3-12	Aa3-13	Aa3-14	Aa3-15 (190)

A manu kake glyph occupies a position of Janus, it stands on the boundary between the old and the new. The added little rhomb at top center in Aa3-10 is presumably the same as in the middle of the preceding hahe glyph.

If counting should begin with Ab1-1, then hahe in Aa3-9 acquires another relevant number:

side b					side a
117		271		274	183		486
	Ab2-36 (118)		Ab5-66 (390)			Aa3-9 (848)
848 = 16 * 53

53 is a number which we recognize from e.g. the G text, where 2 * 53 measures the distance from 365 to 471:

 ... 53 is one more than 52 (weeks in a year) and therefore corresponds to 29 (one more than 28 shining moon nights in a month) ... 265 = 5 * 53, and 53 is a number similar to 29 (the dark night of the month). 52 * 7 = 364 and 53 * 7 = 371 = 471 - 100 ...

The latter statement (cfr at henua) referred to the measure 265 from one takaure glyph to the next:

	67		111			82
Gb3-1		Gb5-6		Gb8-30	Ga1-1		Ga4-1	Ga4-2
180				85
265 = 5 * 53

With manu kake immediately to the right of hahe in Aa3-9 it is not strange to find number 53 associated with this hahe glyph.

The Tahua text possibly contains two major parts, one with 16 * 53 = 848 glyphs and one with 6 * 81 = 486 glyphs. 1334 = 6 * 81 + 16 * 53.

848 can be read as 84 and 8, in which case we can multiply 84 * 8 = 672 = 14 * 48. Or we can read 8 and 48, which gives 8 * 48 = 384. The difference is 6 * 48 = 288, which number we recognize:

		126	446
*Qb5-35 (1)	*Qb5-36			Qb2-9	Qb2-10 (448)
64 + 448 / 2 = 288 days