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If the end of a cycle is illustrated by the glyphs as a 'break' in day number 314 (counted from a presumed winter solstice day), then we should try to count backwards from Hb3-6 (where also the numbers seem to allude to a break) in order to find a beginning of the cycle, 3 * 314 = 942 glyphs earlier:

Hb3-4 Hb3-5 Hb3-6
64 + 250 = 314

With Hb3-6 as day number 64 + 750 / 3 = 314, we can count 3 * 314 = 942. On side b Hb3-6 is glyph number 105. If we subtract 105 from 942 there will remain 837 glyphs, a number greater than 648, the number of glyphs on side a:

a1 50 50 b1 *51 (?) 51
a2 58 108 b2 48 99
a3 52 160 b3 47 146
a4 56 216 b4 51 197
a5 59 275 b5 57 254
a6 *69? 344 b6 54 308
a7 *51? 395 b7 50 358
a8 *54? 449 b8 *54 (?) 412
a9 *53? 502 b9 65 477
a10 *67? 569 b10 67 544
a11 *58? 627 b11 53 597
a12 *21? 648 b12 *51? 648
sum *648? sum *648?

837 - 648 = 189. Counting backwards from line Hb12 we have 51 + 53 + 67 + 65 = 236(!), and 236 - 189 = 47, i.e. Hb9-47 is our glyph:

Glyph numbers and days below are counted from Ha1-4.
Hb9-42 Hb9-43 Hb9-44 Hb9-45 Hb9-46 Hb9-47 (1104)
367 1104 / 3 = 368

We have arrived to the end of Thursday. The cycle of the H text is ending here (at least according to this reading). In order to get the numbers right we must, though, add 192 glyphs (64 days):

Glyph numbers and days below are counted from Hb9-48.
Hb9-42 Hb9-43 Hb9-44 Hb9-45 Hb9-46 Hb9-47 (1296)
367 + 64 = 431 1296 / 3 = 432