If the end of a cycle is
illustrated by the glyphs as a 'break' in day number 314
(counted from a presumed winter solstice day), then we should
try to count backwards from Hb3-6 (where also the numbers seem to
allude to a break) in order to find a beginning of the cycle, 3 * 314 = 942
glyphs earlier:
|
|
|
Hb3-4 |
Hb3-5 |
Hb3-6 |
64 + 250 = 314 |
With Hb3-6 as day number 64 + 750 / 3 = 314,
we can count 3 * 314 = 942. On side b Hb3-6 is glyph number
105. If we subtract 105 from 942 there will remain 837 glyphs, a
number greater than 648, the number of glyphs on side a:
a1 |
50 |
50 |
b1 |
*51 (?) |
51 |
a2 |
58 |
108 |
b2 |
48 |
99 |
a3 |
52 |
160 |
b3 |
47 |
146 |
a4 |
56 |
216 |
b4 |
51 |
197 |
a5 |
59 |
275 |
b5 |
57 |
254 |
a6 |
*69? |
344 |
b6 |
54 |
308 |
a7 |
*51? |
395 |
b7 |
50 |
358 |
a8 |
*54? |
449 |
b8 |
*54 (?) |
412 |
a9 |
*53? |
502 |
b9 |
65 |
477 |
a10 |
*67? |
569 |
b10 |
67 |
544 |
a11 |
*58? |
627 |
b11 |
53 |
597 |
a12 |
*21? |
648 |
b12 |
*51? |
648 |
sum |
*648? |
sum |
*648? |
837 - 648 = 189. Counting backwards from line Hb12 we have 51 + 53 + 67 + 65 =
236(!), and 236 - 189 = 47, i.e. Hb9-47 is our
glyph:
Glyph
numbers and days below are counted from Ha1-4. |
|
|
|
|
|
|
Hb9-42 |
Hb9-43 |
Hb9-44 |
Hb9-45 |
Hb9-46 |
Hb9-47 (1104) |
367 |
1104 / 3 = 368 |
We have arrived to the end of Thursday. The
cycle of the H text is ending here (at least according to this
reading). In order to get the numbers right we must, though, add 192
glyphs (64 days):
Glyph
numbers and days below are counted from Hb9-48. |
|
|
|
|
|
|
Hb9-42 |
Hb9-43 |
Hb9-44 |
Hb9-45 |
Hb9-46 |
Hb9-47 (1296) |
367 + 64 = 431 |
1296 / 3 = 432 |
|