Let me try to explain

Let me try to explain: The sea voyage takes half the time because half the time represents the 'year'. The 'year' from autumn equinox to spring equinox is the season of the sea (consequently a sea voyage), while the other 'year' is the season of the land.

By using a '7th flame' for the Sun it will reach 420 days, which is a station reached by the Moon using 15 periods (à 28 sunlit nights).

Using the perspective of the Moon it will have two 'years' à 210 nights. We remember the Hall of the Two Truths with a double row of 21 judges of the dead:

15 is the number of nights to reach full moon from new moon and 15 is the number of 28-night months needed to reach conjunction with the sun.

Sun has two 'years' and so has Moon. At 210 nights there is a halfway station on the road to the conjunction with the Sun.

Sun has 3 double-months in each 'year', and so has the Moon. Each of the 3 lunar double-months covers 70 nights, that is why Barthel found number 70 in manuscript E.

The sea-voyage of the explorers took 35 nights, in other words ½ a lunar double-month. Another ½ maybe covered time for events on land, though I am not convinced of that. Events on land should be counted by the sun and not by the moon.

The explorer's travel lasted one solar 'year' (3 double-months à 60 days = 180 days) + the time needed for the sea voyage from Easter Island back to Hiva, i.e. 180 + 35 = 215 days in all (given that the return trip took equally long time).

According to my solution the time the explorer's used for activities on land was 180 - 35 - 35 = 110 days. I have deducted another ½ lunar double-month.

They stayed 'one month' at Pu Pakakina and 'one month' at the yam plantation, which leaves us with 110 - 60 = 50 solar days (or 110 - 70 = 40 lunar nights) for the rest of their activities. Though adding the red-marked days below we reach: 5 + 20 + 5 + 7 + 5 + 27 + 5 + 2 = 76, which together with 10 + 10 (= 20 black-marked) days amounts to 96 days:

Event	Date	Duration
Departure of the explorers from Hiva	Vaitu nui 25	35 days
Arrival at Haga Te Pau	He Maro 1	35 days
Construction of house and yam plantation	He Maro 10	10 days
Mako'i surveys the crater	He Maro 15	5 days
Departure from the house	He Anakena 5	20 days
Arrival at Te Pau	He Anakena 10	5 days
Rest at Haga Takaúre		7 days
Departure from Haga Takaúre	He Anakena 18
Rest at Haga Hônu		5 days
Arrival at Ragi Meamea	He Anakena 23
Stay at Oromaga		27 days
Departure for Papa O Pea	Hora iti 20
Stay at Papa O Pea		5 days
Departure for Ahu Akapu	Hora iti 26
Stay at Ahu Akapu		2 days
Departure for Pu Pakakina	Hora iti 29
Stay at Pu Pakakina		'one month'
Departure for yam plantation	Hora nui 1
Stay at yam plantation		'one month'
Explorers greet Hotu Matu'a	Tagaroa uri 15	10 days

From these 76 + 20 = 96 days should be drawn those 35 nights calculated for ½ a lunar double-month, which leaves us with 96 - 35 = 61 nights, not the expected 50 or 40. Lunar periods should not be used on land.

They rested 7 + 5 = 12 days. If we subtract these from 96 days, we find 84. That is probably the solution. They worked twice 42 days (a period in harmony with both sun and moon).